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A teacher wants to determine whether his students have mastered the material in their literature unit. Each student completes a pretest before beginning the unit and a posttest at the end of the unit. The results are in the table. Student Pretest Posttest 1 2 www 3 ww 5 NE H OKO ON 92 81 73 75 70 80 88 96 85 72 3 92 Difference (Posttest - Pretest) 4 -1 The teacher's null hypothesis is that H, 4, = 0, while his alternative hypothesis is 4₂ > 0: Rased on the data in the table and using a significance level of 0.05. what is the correct P

A teacher wants to determine whether his students have mastered the material in their literature unit. Each student completes a pretest before beginning the unit and a posttest at the end of the unit. The results are in the table. Student Pretest Posttest 1 2 www 3 ww 5 NE H OKO ON 92 81 73 75 70 80 88 96 85 72 3 92 Difference (Posttest - Pretest) 4 -1 The teacher's null hypothesis is that H, 4, = 0, while his alternative hypothesis is 4₂ > 0: Rased on the data in the table and using a significance level of 0.05. what is the correct P

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A teacher wants to determine 

### Mastery of Literature Unit Assessment A teacher wants to determine whether his students have mastered the material in their literature unit. Each student completes a pretest before beginning the unit and a posttest at the end of the unit. The results are in the table below: | Student | Pretest | Posttest | Difference (Posttest – Pretest) | |---------|---------|----------|---------------------------------| | 1 | 92 | 96 | 4 | | 2 | 81 | 85 | 4 | | 3 | 73 | 72 | -1 | | 4 | 80 | 82 | 2 | | 5 | 75 | 80 | 5 | | 6 | 70 | 77 | 7 | | 7 | 80 | 78 | -2 | | 8 | 88 | 92 | 4 | | 9 | 82 | 89 | 7 | | 10 | 78 | 78 | 0 | The teacher's null hypothesis is \( H_0: \mu_D = 0 \), while his alternative hypothesis is \( \mu_D > 0 \). Based on the data in the table and using a significance level of 0.05, the task is to determine the correct conclusion.
Transcribed Image Text:### Mastery of Literature Unit Assessment A teacher wants to determine whether his students have mastered the material in their literature unit. Each student completes a pretest before beginning the unit and a posttest at the end of the unit. The results are in the table below: | Student | Pretest | Posttest | Difference (Posttest – Pretest) | |---------|---------|----------|---------------------------------| | 1 | 92 | 96 | 4 | | 2 | 81 | 85 | 4 | | 3 | 73 | 72 | -1 | | 4 | 80 | 82 | 2 | | 5 | 75 | 80 | 5 | | 6 | 70 | 77 | 7 | | 7 | 80 | 78 | -2 | | 8 | 88 | 92 | 4 | | 9 | 82 | 89 | 7 | | 10 | 78 | 78 | 0 | The teacher's null hypothesis is \( H_0: \mu_D = 0 \), while his alternative hypothesis is \( \mu_D > 0 \). Based on the data in the table and using a significance level of 0.05, the task is to determine the correct conclusion.
### Hypothesis Testing Example Below is a table with data regarding two sets of scores: | Unit | Score 1 | Score 2 | Difference | |-------|---------|---------|------------| | 4 | 80 | 82 | 2 | | 5 | 75 | 80 | 5 | | 6 | 70 | 77 | 7 | | 7 | 80 | 78 | -2 | | 8 | 88 | 92 | 4 | | 9 | 82 | 89 | 7 | | 10 | 78 | 78 | 0 | **Hypotheses:** - Null Hypothesis (\(H_0\)): \(\mu_D = 0\) - Alternative Hypothesis (\(H_a\)): \(\mu_D > 0\) **Significance Level:** - \( \alpha = 0.05 \) **Question:** Based on the data in the table and using a significance level of 0.05, what is the correct P-value and conclusion? **Options:** 1. P-value of 0.007478, he must reject the null hypothesis. 2. P-value of 0.005487, he must fail to reject the null hypothesis. 3. P-value of 0.096644, he must reject the null hypothesis. 4. P-value of 0.016644, he must fail to reject the null hypothesis. Analyze the data and use statistical methods to determine the appropriate P-value and conclusion regarding the null hypothesis.
Transcribed Image Text:### Hypothesis Testing Example Below is a table with data regarding two sets of scores: | Unit | Score 1 | Score 2 | Difference | |-------|---------|---------|------------| | 4 | 80 | 82 | 2 | | 5 | 75 | 80 | 5 | | 6 | 70 | 77 | 7 | | 7 | 80 | 78 | -2 | | 8 | 88 | 92 | 4 | | 9 | 82 | 89 | 7 | | 10 | 78 | 78 | 0 | **Hypotheses:** - Null Hypothesis (\(H_0\)): \(\mu_D = 0\) - Alternative Hypothesis (\(H_a\)): \(\mu_D > 0\) **Significance Level:** - \( \alpha = 0.05 \) **Question:** Based on the data in the table and using a significance level of 0.05, what is the correct P-value and conclusion? **Options:** 1. P-value of 0.007478, he must reject the null hypothesis. 2. P-value of 0.005487, he must fail to reject the null hypothesis. 3. P-value of 0.096644, he must reject the null hypothesis. 4. P-value of 0.016644, he must fail to reject the null hypothesis. Analyze the data and use statistical methods to determine the appropriate P-value and conclusion regarding the null hypothesis.
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