A teacher gave her class two functions, f(x) = |x – 5|+4 and g(x) = -x² + 21, and aske for the solution(s) of the equation f(x) = g(x). The answers given by four students are shown below: Betty: only 4 Donna: only 5 Edward: 12 and 5 Gary: -3 and 4 Who found the solution correctly and why? A. Betty, because the solutions are the x-values of the points of intersection of the graphs of f(x) and g(x) but the negative solutions must be discarded because f(x) is an absolute value function. B. Edward, the solutions are the y-values of the points of intersection of the graphs of f(x) and g(x). C. Donna, the solutions are the y-values of the points of intersection of the graphs of f(x) and g(x) but solutions paired with negative x-values must be discarded because f(x) is an absolute value function. D. Gary, the solutions are the x-values of the points of intersection of the graphs of

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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6 of
A teacher gave her class two functions, f(x) = |x – 5+4 and g(x) = -x² + 21, and asked
for the solution(s) of the equation f(x) = g(x). The answers given by four students are
6.
shown below.
Betty: only 4
Donna: only 5
Edward: 12 and 5
Gary: -3 and 4
Who found the solution correctly and why?
A. Betty, because the solutions are the x-values of the points of intersection of the
graphs of f(x) and g(x) but the negative solutions must be discarded because
f(x) is an absolute value function.
B. Edward, the solutions are the y-values of the points of intersection of the graphs
of f(x) and g(x).
C. Donna, the solutions are the y-values of the points of intersection of the graphs
of f(x) and g(x) but solutions paired with negative x-values must be discarded
because f(x) is an absolute value function.
D. Gary, the solutions are the x-values of the points of intersection of the graphs of
f(x) and g(x).
Transcribed Image Text:6 of A teacher gave her class two functions, f(x) = |x – 5+4 and g(x) = -x² + 21, and asked for the solution(s) of the equation f(x) = g(x). The answers given by four students are 6. shown below. Betty: only 4 Donna: only 5 Edward: 12 and 5 Gary: -3 and 4 Who found the solution correctly and why? A. Betty, because the solutions are the x-values of the points of intersection of the graphs of f(x) and g(x) but the negative solutions must be discarded because f(x) is an absolute value function. B. Edward, the solutions are the y-values of the points of intersection of the graphs of f(x) and g(x). C. Donna, the solutions are the y-values of the points of intersection of the graphs of f(x) and g(x) but solutions paired with negative x-values must be discarded because f(x) is an absolute value function. D. Gary, the solutions are the x-values of the points of intersection of the graphs of f(x) and g(x).
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