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(A Task): To access data in a hard disk, it requires time to move the head to the desired track (seek time). Once the head has reached the correct track, we must wait for the desired sector to rotate under the read/write head (rotational latency). The last component of disk access is the time to transfer a block of bits (transfer time). Your task is to: (1) Find out the average seek time, rotational latency, transfer time, and controller delay in the given factors: 512B sector, 5400 RPM, 3 ms average seek time, 100 MB/s transfer rate, 0.2 ms controller overhead, idle disk. (2) What is the average read time in the given factors. (Hint: Average read time = seek time + rotational latency + transfer time + controller delay) (B Task): Given below are the parameters relevant to hard disk access. Sector size 1024 Bytes, 25,000 rpm, 2 ms average seek time, 75 MB/s transfer rate, 0.4 ms controller overhead, and an idle disk. Compute the transfer time for the following cases. (1) Transfer of 512 KB data stored as a contiguous file (2) Transfer of 512 KB data stored in several 2 KB files/segments04:48 PM

(A Task): To access data in a hard disk, it requires time to move the head to the desired track (seek time). Once the head has reached the correct track, we must wait for the desired sector to rotate under the read/write head (rotational latency). The last component of disk access is the time to transfer a block of bits (transfer time). Your task is to: (1) Find out the average seek time, rotational latency, transfer time, and controller delay in the given factors: 512B sector, 5400 RPM, 3 ms average seek time, 100 MB/s transfer rate, 0.2 ms controller overhead, idle disk. (2) What is the average read time in the given factors. (Hint: Average read time = seek time + rotational latency + transfer time + controller delay) (B Task): Given below are the parameters relevant to hard disk access. Sector size 1024 Bytes, 25,000 rpm, 2 ms average seek time, 75 MB/s transfer rate, 0.4 ms controller overhead, and an idle disk. Compute the transfer time for the following cases. (1) Transfer of 512 KB data stored as a contiguous file (2) Transfer of 512 KB data stored in several 2 KB files/segments04:48 PM

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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(A Task): To access data in a hard disk, it requires time to move the head to the desired track (seek time). Once the head has reached the correct track, we must wait for the desired sector to rotate under the read/write head (rotational latency). The last component of disk access is the time to transfer a block of bits (transfer time). Your task is to: (1) Find out the average seek time, rotational latency, transfer time, and controller delay in the given factors: 512B sector, 5400 RPM, 3 ms average seek time, 100 MB/s transfer rate, 0.2 ms controller overhead, idle disk. (2) What is the average read time in the given factors. (Hint: Average read time = seek time + rotational latency + transfer time + controller delay) (B Task): Given below are the parameters relevant to hard disk access. Sector size 1024 Bytes, 25,000 rpm, 2 ms average seek time, 75 MB/s transfer rate, 0.4 ms controller overhead, and an idle disk. Compute the transfer time for the following cases. (1) Transfer of 512 KB data stored as a contiguous file (2) Transfer of 512 KB data stored in several 2 KB files/segments04:48 PM
Transcribed Image Text:(A Task): To access data in a hard disk, it requires time to move the head to the desired track (seek time). Once the head has reached the correct track, we must wait for the desired sector to rotate under the read/write head (rotational latency). The last component of disk access is the time to transfer a block of bits (transfer time). Your task is to: (1) Find out the average seek time, rotational latency, transfer time, and controller delay in the given factors: 512B sector, 5400 RPM, 3 ms average seek time, 100 MB/s transfer rate, 0.2 ms controller overhead, idle disk. (2) What is the average read time in the given factors. (Hint: Average read time = seek time + rotational latency + transfer time + controller delay) (B Task): Given below are the parameters relevant to hard disk access. Sector size 1024 Bytes, 25,000 rpm, 2 ms average seek time, 75 MB/s transfer rate, 0.4 ms controller overhead, and an idle disk. Compute the transfer time for the following cases. (1) Transfer of 512 KB data stored as a contiguous file (2) Transfer of 512 KB data stored in several 2 KB files/segments04:48 PM
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