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A tank holds 138 gallons of water. Initially, at t=0, a solution containing 1/8 lb/gal of a chemical solvent flows into the tank at a rate of 6 gal/min. The mixture then leaves the tank at the same rate. The amount of chemical (water with solvent) at any instant t, inside the tank, corresponds to 3 (1+e-6t/138) O a) 92 3 O b) :(1 – e 6t/138) 92 69 Oc) (1. Be/138 ) - e 69 (1+e-6t/138) 4 d)

A tank holds 138 gallons of water. Initially, at t=0, a solution containing 1/8 lb/gal of a chemical solvent flows into the tank at a rate of 6 gal/min. The mixture then leaves the tank at the same rate. The amount of chemical (water with solvent) at any instant t, inside the tank, corresponds to 3 (1+e-6t/138) O a) 92 3 O b) :(1 – e 6t/138) 92 69 Oc) (1. Be/138 ) - e 69 (1+e-6t/138) 4 d)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(5.2) A tank holds 138 gallons of water. Initially, at t=0, a solution containing 1/8 lb/gal of a chemical solvent flows into the tank at a rate of 6 gal/min. The mixture then leaves the tank at the same rate. The amount of chemical (water with solvent) at any instant t, inside the tank, corresponds to 3 a) (1+e-6£/138) 92 3 O b) (1 -6t/138) 92 69 (1 -e 6t/138) 69 O d) (1+e-6/138 )
Transcribed Image Text:(5.2) A tank holds 138 gallons of water. Initially, at t=0, a solution containing 1/8 lb/gal of a chemical solvent flows into the tank at a rate of 6 gal/min. The mixture then leaves the tank at the same rate. The amount of chemical (water with solvent) at any instant t, inside the tank, corresponds to 3 a) (1+e-6£/138) 92 3 O b) (1 -6t/138) 92 69 (1 -e 6t/138) 69 O d) (1+e-6/138 )
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