(a) T F If a set of m vectors in R" is linearly independent, then m≤n. (b) T F A5x8 matrix cannot have a 2-dimensional null space. (c) T F Ifa 5 x 5 matrix has only 3 distinct eigenvalues, then A cannot be diagonalizable.

Advanced Engineering Mathematics
10th Edition
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Answer true or false. Please answer the first 6

6. (a) T F If a set of m vectors in R" is linearly independent, then m≤n.
(b) T F A5 x 8 matrix cannot have a 2-dimensional null space.
(c) T F If a 5 x 5 matrix has only 3 distinct eigenvalues, then A cannot be diagonalizable.
(d) T F
A linear transformation from R³ to R³ cannot be one-to-one.
(e) T F If r¹ Ar> 0 for some r, then the quadratic form ¹ Ar is positive definite.
(f) T F If a linear system Ax = b is consistent, then rank [Ab] = rank A.
(g) T F If two square matrices are similar, then they have the same eigenvalues.
(h) T F If W is a subspace of R³ and v is a vector in R³, then v is in W or v is in W+.
(i) T F If U is an orthogonal matrix, then the rows of U form an orthonormal basis of R".
(j) T F If A is a 3 x 3 symmetric matrix and if u and v are vectors in R³ such that
Au = 3u and Av = 5v, then u. v = 0.
Transcribed Image Text:6. (a) T F If a set of m vectors in R" is linearly independent, then m≤n. (b) T F A5 x 8 matrix cannot have a 2-dimensional null space. (c) T F If a 5 x 5 matrix has only 3 distinct eigenvalues, then A cannot be diagonalizable. (d) T F A linear transformation from R³ to R³ cannot be one-to-one. (e) T F If r¹ Ar> 0 for some r, then the quadratic form ¹ Ar is positive definite. (f) T F If a linear system Ax = b is consistent, then rank [Ab] = rank A. (g) T F If two square matrices are similar, then they have the same eigenvalues. (h) T F If W is a subspace of R³ and v is a vector in R³, then v is in W or v is in W+. (i) T F If U is an orthogonal matrix, then the rows of U form an orthonormal basis of R". (j) T F If A is a 3 x 3 symmetric matrix and if u and v are vectors in R³ such that Au = 3u and Av = 5v, then u. v = 0.
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