I'm unable to transcribe the text from the blurry image you provided. If you can provide a clearer image or type out the text, I'd be glad to help. However, I can see there is a graph with a grid, likely representing an x-y coordinate system. This setup is typically used to plot data points or graph equations in mathematics. If you have specific questions about graphing or need further explanation, feel free to ask! **Understanding Systems of Linear Equations**A system of linear equations is a set of two or more equations that are considered together. The point where the graphs of these equations intersect is called the solution.### Task 3: Finding the Solution to a System of Equations**a) Complete the table for each linear function.**For the linear functions given, we solve for $ y $ using the equations:1. $ y = \frac{1}{3}x - 3 $2. $ y = -x + 1 $**Table 1:**\[\begin{array}{|c|c|c|}\hlinex & y = \frac{1}{3}x - 3 & (x, y) \\\hline-6 & -5 & (-6,-5) \\\hline-3 & -4 & (-3,-4) \\\hline0 & -3 & (0,-3) \\\hline3 & -2 & (3,-2) \\\hline6 & -1 & (6,-1) \\\hline\end{array}\]**Table 2:**\[\begin{array}{|c|c|c|}\hlinex & y = -x + 1 & (x, y) \\\hline-2 & 3 & (-2,3) \\\hline-1 & 2 & (-1,2) \\\hline0 & 1 & (0,1) \\\hline1 & 0 & (1,0) \\\hline2 & -1 & (2,-1) \\\hline\end{array}\]**b) Graph both equations (lines) on the coordinate plane below.**- Plot each point from the tables on a coordinate plane.- Draw a line through the points for the equation $ y = \frac{1}{3}x - 3 $.- Draw another line through the points for the equation $ y = -x + 1 $.The solution to the system is the intersection of these two lines on the graph.

We have to find the solution of the system of equation y=13x-3 y=-x+1 Solution means the value of x…

A system of linear equations is a set of two or more equations taken together. The point where the two graphs intersect is called the solution. y = x- 3 y = -x +1 3. Use parts a & b to find the solution to the system of equations. a) Complete the table for each linear function. 1 y=,x-3 (x, y) y = -1.x+1 (x, y) (-) (-2,3) -6 -2 -4 (-3,-4) (-1,2)| -3 -3 (0,-3) (0,1) -2 (3,-2) 3 (1,0) -1 (6,-1) -1 (2,-1) b) Graph both equations (lines) on the coordinate plane below. 3. 1. 1. 2. 5.

A system of linear equations is a set of two or more equations taken together. The point where the two graphs intersect is called the solution. y = x- 3 y = -x +1 3. Use parts a & b to find the solution to the system of equations. a) Complete the table for each linear function. 1 y=,x-3 (x, y) y = -1.x+1 (x, y) (-) (-2,3) -6 -2 -4 (-3,-4) (-1,2)| -3 -3 (0,-3) (0,1) -2 (3,-2) 3 (1,0) -1 (6,-1) -1 (2,-1) b) Graph both equations (lines) on the coordinate plane below. 3. 1. 1. 2. 5.

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Question

I'm unable to transcribe the text from the blurry image you provided. If you can provide a clearer image or type out the text, I'd be glad to help.

However, I can see there is a graph with a grid, likely representing an x-y coordinate system. This setup is typically used to plot data points or graph equations in mathematics. If you have specific questions about graphing or need further explanation, feel free to ask!

**Understanding Systems of Linear Equations**

A system of linear equations is a set of two or more equations that are considered together. The point where the graphs of these equations intersect is called the solution.

### Task 3: Finding the Solution to a System of Equations

**a) Complete the table for each linear function.**

For the linear functions given, we solve for $ y $ using the equations:

1. $ y = \frac{1}{3}x - 3 $
2. $ y = -x + 1 $

**Table 1:**
\[
\begin{array}{|c|c|c|}
\hline
x & y = \frac{1}{3}x - 3 & (x, y) \\
\hline
-6 & -5 & (-6,-5) \\
\hline
-3 & -4 & (-3,-4) \\
\hline
0 & -3 & (0,-3) \\
\hline
3 & -2 & (3,-2) \\
\hline
6 & -1 & (6,-1) \\
\hline
\end{array}
\]

**Table 2:**
\[
\begin{array}{|c|c|c|}
\hline
x & y = -x + 1 & (x, y) \\
\hline
-2 & 3 & (-2,3) \\
\hline
-1 & 2 & (-1,2) \\
\hline
0 & 1 & (0,1) \\
\hline
1 & 0 & (1,0) \\
\hline
2 & -1 & (2,-1) \\
\hline
\end{array}
\]

**b) Graph both equations (lines) on the coordinate plane below.**

- Plot each point from the tables on a coordinate plane.
- Draw a line through the points for the equation $ y = \frac{1}{3}x - 3 $.
- Draw another line through the points for the equation $ y = -x + 1 $.

The solution to the system is the intersection of these two lines on the graph.

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