A system of cables is used to support a block as shown in Figure 2 below. Find the tension in the two cables T₁ and T₂ if the mass of the block m = 6.0 kg and the angle 0 = 37.0°. Neglect the mass of the cables. (Hint: Use the conditions of translational equilibrium.) 0 T₁ Figure 2 m T₂
A system of cables is used to support a block as shown in Figure 2 below. Find the tension in the two cables T₁ and T₂ if the mass of the block m = 6.0 kg and the angle 0 = 37.0°. Neglect the mass of the cables. (Hint: Use the conditions of translational equilibrium.) 0 T₁ Figure 2 m T₂
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![**Title: Solving Tension in Cables Using Translational Equilibrium**
**Problem Statement:**
A system of cables is used to support a block as shown in Figure 2 below. Find the tension in the two cables \( T_1 \) and \( T_2 \) if the mass of the block \( m = 6.0 \, \text{kg} \) and the angle \( \theta = 37.0^\circ \). Neglect the mass of the cables.
*(Hint: Use the conditions of translational equilibrium.)*
**Diagram Explanation:**
In Figure 2, a block of mass \( m \) is suspended by two cables. Cable \( T_1 \) is positioned at an angle \( \theta \) with the horizontal ceiling and exerts tension in the direction of the cable. Cable \( T_2 \) is horizontal, exerting tension directly to the right.
**Figure 2:**
- The diagram shows a block suspended from a point where two cables meet.
- \( T_1 \) is the tension in the left cable forming an angle \( \theta \) with the ceiling.
- \( T_2 \) is the tension in the right cable, which is horizontal.
- The block with mass \( m \) hangs directly downward from the point where the cables meet.
**Concepts Involved:**
- Translational equilibrium occurs when the sum of forces in any direction is zero.
- The forces involved include gravitational force on the block (its weight) and tensions in the cables.
**Steps to Solve:**
1. **Resolve Forces:**
- Consider the vertical and horizontal components of forces.
2. **Vertical Forces:**
- The vertical component of \( T_1 \) (\( T_1 \sin \theta \)) balances the weight of the block (\( mg \)).
- Equation: \( T_1 \sin \theta = mg \).
3. **Horizontal Forces:**
- The horizontal component of \( T_1 \) (\( T_1 \cos \theta \)) balances \( T_2 \).
- Equation: \( T_1 \cos \theta = T_2 \).
4. **Calculations:**
- Use the equations to solve for \( T_1 \) and \( T_2 \).
Understanding and applying these principles will allow you to find the tensions in the cables when](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fccff42f4-47ae-4312-8e0a-a323e46c7ccc%2Ff4f44044-60af-4cd6-9216-0ec958d29ecb%2Fvinoyy_processed.png&w=3840&q=75)
Transcribed Image Text:**Title: Solving Tension in Cables Using Translational Equilibrium**
**Problem Statement:**
A system of cables is used to support a block as shown in Figure 2 below. Find the tension in the two cables \( T_1 \) and \( T_2 \) if the mass of the block \( m = 6.0 \, \text{kg} \) and the angle \( \theta = 37.0^\circ \). Neglect the mass of the cables.
*(Hint: Use the conditions of translational equilibrium.)*
**Diagram Explanation:**
In Figure 2, a block of mass \( m \) is suspended by two cables. Cable \( T_1 \) is positioned at an angle \( \theta \) with the horizontal ceiling and exerts tension in the direction of the cable. Cable \( T_2 \) is horizontal, exerting tension directly to the right.
**Figure 2:**
- The diagram shows a block suspended from a point where two cables meet.
- \( T_1 \) is the tension in the left cable forming an angle \( \theta \) with the ceiling.
- \( T_2 \) is the tension in the right cable, which is horizontal.
- The block with mass \( m \) hangs directly downward from the point where the cables meet.
**Concepts Involved:**
- Translational equilibrium occurs when the sum of forces in any direction is zero.
- The forces involved include gravitational force on the block (its weight) and tensions in the cables.
**Steps to Solve:**
1. **Resolve Forces:**
- Consider the vertical and horizontal components of forces.
2. **Vertical Forces:**
- The vertical component of \( T_1 \) (\( T_1 \sin \theta \)) balances the weight of the block (\( mg \)).
- Equation: \( T_1 \sin \theta = mg \).
3. **Horizontal Forces:**
- The horizontal component of \( T_1 \) (\( T_1 \cos \theta \)) balances \( T_2 \).
- Equation: \( T_1 \cos \theta = T_2 \).
4. **Calculations:**
- Use the equations to solve for \( T_1 \) and \( T_2 \).
Understanding and applying these principles will allow you to find the tensions in the cables when
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