A system has three particles A, B and C. The masses of these particles are mA 3 kg. For particle A, position vector TA = lî + 2ĵ + 2k with velocity vector - 5î + 23 + 5k. For particle B, position vector iB = 2î – 13 – 2k with velocity vector - 3i + 13 – 3k. For particle C, position vector ic = 4i – 5j + Ok with velocity vector 0ê – 13 – 2k. 2 kg, mB 3 kg and mc VA UR = Find the angular momentum about the center of mass (sometimes called center of gravity). HG with units of kg*m^2/s
A system has three particles A, B and C. The masses of these particles are mA 3 kg. For particle A, position vector TA = lî + 2ĵ + 2k with velocity vector - 5î + 23 + 5k. For particle B, position vector iB = 2î – 13 – 2k with velocity vector - 3i + 13 – 3k. For particle C, position vector ic = 4i – 5j + Ok with velocity vector 0ê – 13 – 2k. 2 kg, mB 3 kg and mc VA UR = Find the angular momentum about the center of mass (sometimes called center of gravity). HG with units of kg*m^2/s
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Q.9
Transcribed Image Text:A system has three particles A, B and C. The masses of these particles are mA = 2 kg, mB =
mc = 3 kg. For particle A, position vector TA = lî + 23 + 2k with velocity vector
- 5i + 23 + 5k. For particle B, position vector iB = 2î – 13 – 2k with velocity vector
3â + 1ộ – 3k. For particle C, position vector ic = 4î – 53 + Ok with velocity vector
0å – 1ŷ – 2k.
3 kg and
VA
VB
%3D
Find the angular momentum about the center of mass (sometimes called center of gravity).
Hg
i +
with units of kg*m^2/s
Cubuit Outin
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