A system has 5 processes and 5 types of resources. The current state of the system is asfollows:Process Allocated (C)Requested (R)Available (A)II₁1 2 2 3 103 3 3 3A 2 4 1 7II22 1201623 2 3II35 1 0029 322 0II4202 1 13 1402II52011 0 12 4 505What is the smallest values of \ for which the system is in a safe state? Justify youranswer.

We employed the Banker's Algorithm to find the lowest values of available resources (A) for which…

Answered: A system has 5 processes and 5 types of…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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An operating system has three user processes, and each of these processes consumes two units of the resource R. The operating system consumes a total of twelve units via R. The absolute minimum number of R units required to preclude the chance of deadlocks occurring is
An operating system uses a total of two units of the resource R for each of its three user processes. The operating system uses a total of 12 units of R. The absolute minimum number of R units that must be used to guarantee that there are no deadlocks is
Task 3 A system has 5 processes and 5 types of resources. The current state of the system is as follows: Process Allocated (C) Requested (R) Available (A) II₁ 1 2 2 3 1 0 3 3 3 3 X 2 4 1 7 П2 2 1 20 1 6 23 23 II3 5 1002 9 3 20 ΠΑ 20 21 1 3 14 02 II5 201 10 12 4 5 0 5 What is the smallest values of \ for which the system is in a safe state? Justify your answer.
An operating system uses a total of two units of the resource R for each of its three user processes. The operating system uses a total of 12 units of R. The absolute minimum number of R units that must be used to guarantee that there are no deadlocks is
A system has four processes and five allocatable resources. The current allocation and maximum needs are as follows: Allocated Maximum Available Process A 102111121300x11 20110 22210 11010 21310 11110112 21 Process B Process C Process D The smallest value of x for which the above system in safe state is
An operating system uses the Banker's algorithm for deadlock avoidance when managing the allocation of three resource types X, Ý, and Z to three processes PO, P1, and P2. The table given below presents the current system state. There are 3 instances of type X, 2 instances of type Y and 2 instances of type Z still available. The system is currently in a safe state. Answer the following questions! Allocation Max X Y z X Y PO 0 1 8 4 3 (a) If PO requests 2 instances of Z during the P1 3 2 current state, can it be granted? Explain! (b) If P1 requests 2 instances of X during the P2 2 1 1 3 3 3 current state, can it be granted? Explain! CO
COURSE Operating System Only correct answer will be upvoted. Else downvoted.
Bounded waiting requires that \A bound must exist on the number of times that other processes are allowed to enter their critical sections a) true b) false
Exercises - Scheduling Score: 7.8/20 3/10 answered Question 4 Using the priority list T4, T1, T7, T9, T8, T6, T2, T5, T3, schedule the project below with two processors. Task Time Required Tasks that must be completed first T1 6 T2 7 T3 9 T4 10 T1 T5 12 T1 T6 2 T2, T3 T7 6 T4, T5 T8 6 T5, T6 T9 11 T5, T6 Task 5 is done by Select an answer starting at time Task 8 is done by Select an answer starting at time The finishing time for the schedule is Progress 0.
In the context of operating systems
An operating system contains 3 user processes, each process requiring 2 units of the resource R. The minimum number of units ofR required such that there is no possibility of deadlock on R is A 6 B 3 С 5 D 4
An operating system has three user processes, and each of these processes consumes two units of the resource R. The operating system consumes a total of twelve units via R. The absolute minimum number of R units required to preclude the chance of deadlocks occurring is

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