A survey of women who are the main meal preparers in their households reported that 80% know that high fat intake may lead to health problems.  Suppose that this survey was based on a random sample of 750 women with mean equal to 100. With 95% confidence level, How accurate do you expect this percentage to be in estimating the actual population percentages?   Question 9 options:   No correct answer   Within 0.029   Within 100.029   Within 99.971

Q: In a survey, 16 people were asked how much they spent on their child's last birthday gift. The…

A: Given that : n=16 Standard deviation =$13 Mean = $49 We have to calculate 99% Confidence level :

Q: In a survey, 30 people were asked how much they spent on their child's last birthday gift. The…

A: Solution:

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city…

A:

Q: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The…

A: We have given that,  Sample mean (x̄) = 34, standard deviation (s)=6 and sample size (n) = 10 Then,…

Q: In a survey, 18 people were asked how much they spent on their child's last birthday gift. The…

A: Thus, sample mean = 40. Sample standard deviation, s is 15. The sample size, n is 18. The degrees of…

Q: In a survey, 12 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey,  20 people were asked how much they spent on their child's last birthday gift.  The…

A: Solution: Given information: n= 20 Sample size  x= $38 Sample mean s= $7 Sample standard deviation

Q: In a survey, 30 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: interval at a 95% confidence level. Give your answers to one decimal place. Interpret your…

A: Given : Sample Size, n = 18 Sample Mean, x̄ = 35 sample standard…

Q: You are looking into selling prices of Subaru Outback from a website where users report their…

A: Formula :

Q: In a survey, 27 people were asked how much they spent on their child's last birthday gift. The…

A: Given that n=27, s=6, Confidence level=95%

Q: One personality test available on the World Wide Web has a subsection designed to assess the…

A: We have given that Mean(µ) = 140 Sample mean (x̅) = 134 Standard deviations (s) = 28

Q: survey, 20 people were asked how much they spent on their child's last birthday gift. The results…

A: Given that  Sample size (n) = 20 The results are normally distributed. (Bell shaped) Sample Mean…

Q: This was a question on my homework and I would like to know if I answered it correctly. Thank you…

A: Odds (O):The “odds” of the occurrence of an event is the ratio of the number of occurrences of the…

Q: In a survey, 32 people were asked how much they spent on their child's last birthday gift. The…

A: Given  sample size n=32 mean x¯=$33 standard deviation s=$12 confidence level =80%,…

Q: An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city…

A: Given, Sample size = 719 Sample mean = 23.7 Population standard deviation = 9.7   Since the…

Q: In a survey, 17 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: Find the standard error for comparing the means.  Construct a 95% confidence interval for the…

A: The sample mean of the body dissatisfaction assessment score was 13.4 (s=7.9) for 15 lean sports…

Q: In a survey, 24 people were asked how much they spent on their child's last birthday gift. The…

A: From the available information, Sample size, n =24 Sample mean, x = 31 Sample standard deviation, s…

Q: In a survey, 21 people were asked how much they spent on their child's last birthday gift. The…

A: A confidence interval is an interval that is used to estimate the unknown parameter. The lowest…

Q: Which multiple comparison test provide better protection against misses or type II errors? Describe…

A: Here's the explanation is as follows; The multiple comparisons,  occurs when one considers a set of…

Q: In a survey, 21 people were asked how much they spent on their child's last birthday gift. The…

A: It is given that sample mean is 50 and standard deviation is 12.

Q: In a survey, 18 people were asked how much they spent on their child's last birthday gift. The…

A: According to the provided information, Mean = 34 Standard deviation = 12 Significance level = 90%…

Q: In a survey, 18 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A: See the handwritten solution

Q: In a survey, 30 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 21 people were asked how much they spent on their child's last birthday gift. The…

A: From the provided information, Sample size (n) = 21 Sample mean (x̅) = $46 Sample standard deviation…

Q: In a survey, 20 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=20Mean(x)=50standard deviation(s)=19c=90%

Q: A grocer finds that the cantaloupes in his store have weights with mean 0.7 kg and standard…

A: Given, Mean weight of cantaloupes is 700 gm. Standard deviation is 53 gm

Q: In a survey, 12 people were asked how much they spent on their child's last birthday gift. The…

A: Sample mean (x̄) = $ 30, standard deviation        (s) = $ 8 and sample size (n) = 12 Then,  We will…

Q: In a survey, 25 people were asked how much they spent on their child's last birthday gift. The…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: In a survey, 32 people were asked how much they spent on their child's last birthday gift. The…

A: