A survey of several 1010 to 1111 year olds recorded the following amounts spent on a trip to the mall: $23.22,$9.71,$14.34,$23.05,$16.61,$7.22,$22.15$⁢23.22,$⁢9.71,$⁢14.34,$⁢23.05,$⁢16.61,$⁢7.22,$⁢22.15 Construct the 99%99% confidence interval for the average amount spent by 1010 to 1111 year olds on a trip to the mall. Assume the population is approximately normal. Copy Data Step 2 of 4:  Calculate the sample standard deviation for the given sample data. Round your answer to two decimal places.

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A:

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A: The critical value at 99% confidence level from standard normal table will be:   Following…

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A: Note: Thank you for the question. Since multiple sub parts are posted, according to our policy, we…

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A:

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A:

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A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

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A:

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Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: Given; x=561n=935The level of significance is;α=1-0.95=0.05 (a) The best point estimate of the…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.