A survey of 61 comma 64661,646 people included several questions about office relationships. Of the respondents, 25.725.7% reported that bosses scream at employees. Use a 0.050.05 significance level to test the claim that more than 1 divided by 41/4 of people say that bosses scream at employees. How is the conclusion affected after learning that the survey is an online survey in which Internet users chose whether to respond? Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method. Use the normal distribution as an approximation of the binomial distribution. Identify the null and alternative hypotheses. Choose the correct answer below. A. H0: pequals=0.750.75 H1: pnot equals≠0.750.75 B. H0: pequals=0.750.75 H1: pgreater than>0.750.75 C. H0: pequals=0.250.25 H1: pnot equals≠0.250.25 D. H0: pequals=0.250.25 H1: pless than<0.250.25 E. H0: pequals=0.250.25 H1: pgreater than>0.250.25 Your answer is correct. F. H0: pequals=0.750.75 H1: pless than<0.750.75 The test statistic is zequals=nothing. (Round to two decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A survey of

61 comma 64661,646

people included several questions about office relationships. Of the respondents,

25.725.7%

reported that bosses scream at employees. Use a

0.050.05

significance level to test the claim that more than

1 divided by 41/4

of people say that bosses scream at employees. How is the conclusion affected after learning that the survey is an online survey in which Internet users chose whether to respond? Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method. Use the normal distribution as an approximation of the binomial distribution.

Identify the null and alternative hypotheses. Choose the correct answer below.

H0:

pequals=0.750.75

H1:

pnot equals≠0.750.75

H0:

pequals=0.750.75

H1:

pgreater than>0.750.75

H0:

pequals=0.250.25

H1:

pnot equals≠0.250.25

H0:

pequals=0.250.25

H1:

pless than<0.250.25

H0:

pequals=0.250.25

H1:

pgreater than>0.250.25

Your answer is correct.

H0:

pequals=0.750.75

H1:

pless than<0.750.75

The test statistic is

zequals=nothing.

(Round to two decimal places as needed.)

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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