A survey of 480 students showed that 132 of them purchase books online. Find a 94% confidence interval estimate of the proportion of all students who purchase books online. 1) Critical Value = 2) Margin of Error (round answer to 3 decimal places) = 3) Confidence Interval (Type lower limit in the first textbox, upper limit in the second textbox. Express answers in decimal rounded to 3 decimal places): < p <
Q: Out of 500 people sampled, 380 had kids. Based on this, construct a 90% confidence interval for the…
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Q: Out of 100 people sampled, 47 had kids. Based on this, construct a 99% confidence interval for the…
A: X = 47 N = 100 99% confidence level
Q: Out of 200 people sampled, 62 had kids. Based on this, construct a 95% confidence interval for the…
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Q: Out of 600 people sampled, 546 had kids. Based on this, construct a 99% confidence interval for the…
A: We have given that, Sample size (n) = 600 and favorable cases (X) = 546 Then, We will find the…
Q: Out of 400 people sampled, 216 had kids. Based on this, construct a 90% confidence interval for the…
A: From the Standard Normal Table, the value of z* for 90% confidence is 1.645. The sample proportion…
Q: Out of 300 people sampled, 258 had kids. Based on this, construct a 99% confidence interval for the…
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Q: Out of 600 people sampled, 228 had kids. Based on this, construct a 90% confidence interval for the…
A: The following information is given Sample size n=600 Number of kids x= 228 Proportion p^=228600=0.88…
Q: Out of 200 people sampled, 164 had kids. Based on this, construct a 99% confidence interval for the…
A: Solution-: Let, X= Number of people had kids among 200 people Given: n=200,X=164,α=0.01 We find 90%…
Q: Out of 600 people sampled, 282 had kids. Based on this, construct a 95% confidence interval for the…
A: Out of 600 people sampled, 282 had kids. Based on this, construct a 95% confidence interval for the…
Q: construct a 99% confidence interval for the true population proportion of people with kids.
A: Given : n=600 , X=84 , α=0.01 Our aim is to construct a 99% confidence interval for the true…
Q: Out of 500 people sampled, 375 had kids. Based on this, construct a 99% confidence interval for the…
A: Number of people (n) = 500 Number of people had kids (n) = 375 Find z-critical value:…
Q: Out of 400 people sampled, 128 had kids. Based on this, construct a 99% confidence in true…
A: Given data,n=400x=128Point estimate isp=xn=128400=0.32Construct 99% confidence interval?
Q: t of 500 people sampled, 180 had kids. Based on this, construct a 95% confidence interval for the…
A: Given data,n=500x=180construct a 95% confidence interval?
Q: Out of 400 people sampled, 100 had kids. Based on this, construct a 90% confidence interval for the…
A: We have given that , Sample of 400 people. Favarable cases = 100 kids. We have to find 90%…
Q: Out of 500 people sampled, 35 had kids. Based on this, construct a 99% confidence intervalul…
A: given data n = 500 x = 35 99% ci for p = ?
Q: In a sample of 270 adults, 173 had children. Construct a 99% confidence interval for the true…
A: The sample size n= 270. The sample proportion is 173/270. The absolute value of Zα/2 is 2.5758 using…
Q: Out of 400 people sampled, 164 had kids. Based on this, construct a 95% confidence interval for the…
A: Given:Sample size = n = 400 peoplePeople having kids = x = 164Confidence level = 0.95So, α = 1 –…
Q: Out of 500 people sampled, 355 had kids. Based on this, construct a 90% confidence interval for the…
A: By using the given information, we have Out of 500 people sampled, 355 had kids. 90% confidence…
Q: Out of 300 people sampled, 207 had kids. Based on this, construct a 90% confidence interval for the…
A: Givensample size(n)=300x=207sample proportion(p^)=xn=207300=0.69confidence level=90%
Q: Out of 500 people sampled, 280 had kids. Based on this, construct a 95% confidence interval for the…
A: Given Information:n=500x=280c=95%=0.95
Q: In a sample of 530 adults, 445 had children. Construct a 99% confidence interval for the true…
A: We have given that, Favorable cases (X) = 445 and sample size (n)=530 Then, We will find the 99%…
Q: Out of 600 people sampled, 492 had kids. Based on this, construct a 99% confidence interval for the…
A:
Q: In a sample of 420 adults, 349 had children. Construct a 90% confidence interval for the true…
A: given data sample size (n) = 420favorable outcomes (x) = 34990% ci p.
Q: Out of 400 people sampled, 200 had kids. Based on this, construct a 99% confidence interval for the…
A: Number of peoples (n) =400 Number of peoples with kids (x) =200 Find z-critical value:…
Q: Out of 200 people sampled, 132 had kids. Based on this, construct a 90% confidence interval for the…
A: given data, x=132n=200CI=0.90α=1-0.90=0.10p^=xn=132200=0.66
Q: In a sample of 300 adults, 267 had children. Construct a 90% confidence interval for the true…
A: To construct a 90% confidence interval for the population proportion, we'll use the formula for the…
Q: Out of 300 people sampled, 135 had kids. Based on this, construct a 99% confidence interval for the…
A: According to the given information in this question We need to construct 99% confidence interval
Q: Out of 200 people sampled, 78 had kids. Based on this, construct a 99% confidence interval for the…
A:
Q: Out of 500 people sampled, 150 had kids. Based on this, construct a 99% confidence interval for the…
A: To construct a 99% confidence interval for the true population proportion of people with kids, we…
Q: 300 people sampled, 120 had kids. Based on this, construct a 90% confidence interval for the true…
A: The value of z at a 90% confidence level is 1.645, which can be obtained by using the standard…
Q: Out of 300 people sampled, 258 had kids. Based on this, construct a 99% confidence interval for the…
A:
Q: t of 300 people sampled, 237 had kids. Based on this, construct a 90% confidence interval for the…
A: given data, n=300x=had kids=237p^=xn=237300=0.79CI=0.90α=1-0.90=0.10
Q: Out of 100 people sampled, 14 had kids. Based on this, construct a 95% confidence interval for the…
A: Given data, x=14 n=100 p=x/n= 14/100= 0.14 The z value at 95% confidence is Z=1.96
Q: Out of 300 people sampled, 258 had kids. Based on this, construct a 99% confidence interval for the…
A:
Q: Out of 500 people sampled, 280 had kids. Based on this, construct a 99% confidence interval for the…
A: Given information Total people sampled (n) = 500 No of people having kids(x) = 280 Confidence level…
Q: Out of 400 people sampled, 212 had kids. Based on this, construct a 90% confidence interval for the…
A: From the provided information, Sample size (n) = 400 212 had kids that is x = 212 Confidence level =…
Q: Out of 100 people sampled, 27 had kids. Based on this, construct a 95% confidence interval for the…
A:
Q: Out of 100 people sampled, 48 had kids. Based on this, construct a 99% confidence interval for the…
A:
Q: Out of 300 people sampled, 270 had kids. Based on this, construct a 90% confidence interval for the…
A: given data, n=300x=270CI=0.90α=1-0.90=0.10Zc:=Zα/2=Z0.10/2=Z0.05=1.645 [from excel function , code…
Q: Out of 100 people sampled, 48 had kids. Based on this, construct a 90% confidence interval for the…
A:
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- Out of 100 people sampled, 68 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to three places < p <Out of 200 people sampled, 14 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to four placesOut of 300 people sampled, 198 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to three places < p <Out of 500 people sampled, 280 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to four places < p <You recently sent out a survey to determine if the percentage of adults who use social media has changed from 62%, which was the percentage of adults who used social media five years ago. Of the 2283 people who responded to survey, 1635 stated that they currently use social media.a) Use the data from this survey to construct a 94% confidence interval estimate of the proportion of adults who use social media. Record the result below in the form of (#,#)(#,#). Round your final answer to four decimal places.Out of 300 people sampled, 66 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places.Out of 600 people sampled, 120 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to three places< p <Out of 600 people sampled, 192 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to four placesOut of 100 people sampled, 26 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to four places < p <Out of 300 people sampled, 219 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places.Out of 600 people sampled, 528 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to four placesIn a sample of 300 adults, 198 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places RectanRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. FreemanMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman