A survey of 41 people was conducted to compare their self-reported height to their actual height. The difference between reported height and actual height was calculated. You're testing the claim that the mean difference is greater than 1. From the sample, the mean difference was 1.1, with a standard deviation of 0.54. Calculate the test statistic, rounded to two decimal places = Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.05 significance level. The null and alternative hypothesis would be:   H0:μN≤μDH0:μN≤μD H1:μN>μDH1:μN>μD H0:μN=μDH0:μN=μD H1:μN≠μDH1:μN≠μD H0:μN≥μDH0:μN≥μD H1:μN<μDH1:μN<μD H0:pN=pDH0:pN=pD H1:pN≠pDH1:pN≠pD H0:pN≥pDH0:pN≥pD H1:pNpDH1:pN>pD The test is: left-tailed two-tailed right-tailed The sample consisted of 80 night students, with a sample mean GPA of 2.55 and a standard deviation of 0.03, and 80 day students, with a sample mean GPA of 2.6 and a standard deviation of 0.06. The test statistic is:  (to 2 decimals)

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A survey of 41 people was conducted to compare their self-reported height to their actual height. The difference between reported height and actual height was calculated.

You're testing the claim that the mean difference is greater than 1.

From the sample, the mean difference was 1.1, with a standard deviation of 0.54.

Calculate the test statistic, rounded to two decimal places

=

Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.05 significance level.

The null and alternative hypothesis would be:

 

H0:μN≤μDH0:μN≤μD
H1:μN>μDH1:μN>μD
H0:μN=μDH0:μN=μD
H1:μN≠μDH1:μN≠μD
H0:μN≥μDH0:μN≥μD
H1:μN<μDH1:μN<μD
H0:pN=pDH0:pN=pD
H1:pN≠pDH1:pN≠pD
H0:pN≥pDH0:pN≥pD
H1:pN<pDH1:pN<pD
H0:pN≤pDH0:pN≤pD
H1:pN>pDH1:pN>pD



The test is:

left-tailed
two-tailed
right-tailed

The sample consisted of 80 night students, with a sample mean GPA of 2.55 and a standard deviation of 0.03, and 80 day students, with a sample mean GPA of 2.6 and a standard deviation of 0.06.

The test statistic is:  (to 2 decimals)

The p-value is:  (to 2 decimals)

Based on this we:

  • Fail to reject the null hypothesis
  • Reject the null hypothesis
Expert Solution
Step 1

Solution:

Given information:

n= 41 sample size xd=1.1 Difference of sample mean sd= 0.54 Difference of sample standard deviation μd=1  Difference of population mean 

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