A survey found that the American family generates an average of 17.2 pounds of glass garbage each year. Assume the standard deviation of the distribution is 2.5 pounds. Find the probability that the mean of a sample of 38 families will be between 17.5 and 18.5 pounds. Assume that the sample is taken from a large population and the correction factor can be ignored. Round your final answer to four decimal places and intermediate I-value calculations to two decimal places. P(17.5

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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A survey found that the American family generates an average of 17.2 pounds of glass garbage each year. Assume the standard deviation of the distribution is 2.5 pounds. Find the probability that the mean of a sample of 38 families will be between 17.5 and 18.5 pounds. Assume that the sample is taken from a large population and the correction factor can be ignored. Round your final answer to four decimal places and intermediate z-value calculations to two decimal places.

\[ P(17.5 < \bar{X} < 18.5) = \]
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This exercise involves calculating the probability of the sample mean falling within a specified range, given the population mean and standard deviation. To solve this, use the formula for the standard error and the z-score for the normal distribution.
Transcribed Image Text:A survey found that the American family generates an average of 17.2 pounds of glass garbage each year. Assume the standard deviation of the distribution is 2.5 pounds. Find the probability that the mean of a sample of 38 families will be between 17.5 and 18.5 pounds. Assume that the sample is taken from a large population and the correction factor can be ignored. Round your final answer to four decimal places and intermediate z-value calculations to two decimal places. \[ P(17.5 < \bar{X} < 18.5) = \] [Input box for answer] This exercise involves calculating the probability of the sample mean falling within a specified range, given the population mean and standard deviation. To solve this, use the formula for the standard error and the z-score for the normal distribution.
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