### Problem StatementA super ball of mass 0.1 kg is dropped from a height of 3.0 m above the floor. It bounces off the table and rises to a height of 2.6 m. This is an elastic collision similar to the carts with springs in your lab.**Given Data:**- Mass of the ball: \( 0.1 \) kg- Initial height: \( 3.0 \) m- Final height: \( 2.6 \) m#### Tasks:**a. Calculate the velocity of the ball the instant before it reached ground level, \( v_1 \).****Hint:** You can use conservation of mechanical energy and the height it is dropped from to get this velocity.**b. Now use conservation of energy to calculate the velocity the ball must have after the collision at the instant it leaves the ground to reach a height of 2.6 m.****Graphical Representation:***Figure 8-21*- The diagram shows a super ball of mass \( 0.1 \) kg dropped from a height marked "3.0 m".- The graph depicts the motion of the ball falling under gravity with the direction of the movement indicated by a downward arrow labeled "+x-DIRECTION".**c. These velocities \( v_1 \) and \( v_2 \) are the initial and final velocities for the collision with the ground. Use them to calculate the change in momentum of the ball. Don’t forget the directions are not the same so one will be + and the other -.### Explanation:1. To find the velocity \( v_1 \) before the ball hits the ground: - Utilize the principle of the conservation of mechanical energy, equating the potential energy at the height of 3.0 m to the kinetic energy just before hitting the ground.2. To find the velocity \( v_2 \) after the ball leaves the ground to reach a height of 2.6 m: - Again use conservation of energy, equating the kinetic energy just after leaving the ground to the potential energy at the height of 2.6 m.3. Compute the change in momentum: - Momentum is calculated using the formula \( p = mv \). - The change in momentum will be the difference between the momentum before collision and after collision, keeping direction in account (+ and -).Understanding these principles and performing

a) Apply the energy conservation equation to determine the velocity of the ball just before reaching…

A super ball of mass 0.1 kg is dropped from a height of 3.0 m above the floor. It bounces off the table and rises to a height of 2.6 m. This is an elastic col- lision similar to the carts with springs in your lab. a. Calculate the velocity of the ball the instant before it reached ground level, V₁. Hint: You can use conservation of mechanical energy and the height it is dropped from to get this velocity. +x-DIRECTION Now use conservation of energy to calculate the velocity the ball must have after the collision at the instant it leaves the ground to reach a height of 2.6 m. Figure 8-21 C. These velocities are the initial and final velocities for the collision with the ground. Use them to calculate the change in momentum of the ball. Don't forget the directions are not the same so one will be +₂ the other -. b. 2.0 m

A super ball of mass 0.1 kg is dropped from a height of 3.0 m above the floor. It bounces off the table and rises to a height of 2.6 m. This is an elastic col- lision similar to the carts with springs in your lab. a. Calculate the velocity of the ball the instant before it reached ground level, V₁. Hint: You can use conservation of mechanical energy and the height it is dropped from to get this velocity. +x-DIRECTION Now use conservation of energy to calculate the velocity the ball must have after the collision at the instant it leaves the ground to reach a height of 2.6 m. Figure 8-21 C. These velocities are the initial and final velocities for the collision with the ground. Use them to calculate the change in momentum of the ball. Don't forget the directions are not the same so one will be +₂ the other -. b. 2.0 m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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