18.) see photo for details, please provide full body diagram with solution **Problem Statement:**A submarine rests on the ocean floor at a depth of 800 meters. Calculate:A) The pressure at this depth.B) The force acting on a 0.6 m² hatch on the conning tower of the submarine, assuming that the pressure inside the hatch is 1 atmosphere.---**Detailed Explanation:**To solve this problem, we need to consider the concepts of pressure in fluids and forces exerted on surfaces due to pressure differences.**Part A: Calculating Pressure at Depth**The pressure at a certain depth in a fluid is given by the formula:\[ P = P_0 + \rho g h \]Where:- \( P \) is the pressure at depth.- \( P_0 \) is the atmospheric pressure at the surface (1 atmosphere = 101,325 Pa).- \( \rho \) is the density of seawater (approx. 1025 kg/m³).- \( g \) is the acceleration due to gravity (9.81 m/s²).- \( h \) is the depth (800 m).Substitute these values to find the pressure at 800 meters.**Part B: Calculating the Force on the Hatch**Once the pressure at 800 meters is found, the force on the hatch can be determined using:\[ F = (P - P_{\text{inside}}) \cdot A \]Where:- \( F \) is the force acting on the hatch.- \( P_{\text{inside}} \) is the pressure inside the hatch (1 atmosphere = 101,325 Pa).- \( A \) is the area of the hatch (0.6 m²).Calculate the difference in pressure between the outside and the inside of the hatch, and then multiply by the area to get the force.

It is given that the depth of the ocean floor is, h=800 m It is known that the pressure on an object at a depth h in fluid is, P=P0+ρgh Here, ρ is the density of fluid, P0 is atmospheric pressure, g is gravity and h is height. Density of water is, ρ=1000 kg/m3(a) It is known that atmospheric pressure, P0=1.013×105 Pa Pressure at depth h=800 m is, P=P0+ρgh=(1.013×105 Pa)+(1000 kg/m3×10 ms-2×800 m)=(1.013×105 )+(80×105)=81.013×105 Pa Final answer: Pressure at depth h=800 m is, P=81.013×105 Pa (b) It is given that the area of the hatch is, A=0.6 m2 Force acting on the hatch can be given as, F=PA Here, P is the net pressure on the hatch and A is the area of the hatch. Net pressure on the hatch is, Pnet=P-Pinside=81.013×105-1.013×105=80×105 Pa So, the force acting on the hatch is, F=PA=80×105 Pa0.6 m2=133.33 ×105 N Final answer: The force acting on the hatch on the conning tower of the submarine is F=133.33 ×105 N

Answered: A submarine rests on the ocean floor at…

A submarine rests on the ocean floor at a depth of 800 m. Calculate A) the pressure at this depth and B) the force acting on a 0.6 m² hatch on the conning tower of the submarine, assuming that the pressure inside the hatch is 1 atmosphere.