A study was performed to assess the feasibility of a national random digit dialing cellular phone survey among young adults age 18–34 (Genderson et al., [17]). lt was reported that 3.1% of respondents were eligible to participate and that 52% of eligible respondents agreed to participate. Suppose 1000 potential participants are contacted to participate in the survey. What is the probability that at least 10 of the 1000 participants will be eligible and agree to participate?

A study was performed to assess the feasibility of a national random digit dialing cellular phone survey among young adults age 18–34 (Genderson et al., [17]). lt was reported that 3.1% of respondents were eligible to participate and that 52% of eligible respondents agreed to participate. Suppose 1000 potential participants are contacted to participate in the survey. What is the probability that at least 10 of the 1000 participants will be eligible and agree to participate?

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is lower among community college students. She selects 352 community college students at random and finds that 122 of them have a smart phone. In testing the hypotheses: Ho: p= 0.33 versus Ha: p < 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for #3 and #4. 4. Find the p-value.-- 5. The communication professor should the null hypothesis.
According to a report, 57.5% of murders are committed with a firearm. (a) If 200 murders are randomly selected, how many would we expect to be committed with a firearm? (b) Would it be unusual to observe 136 murders by firearm in a random sample of 200 murders? Why? (a) We would expect to be committed with a firearm.
In a previous poll, 35% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 1088 adults with children under the age of 18 were selected at random, and 361 of those 1088 adults reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use the a = 0.05 significance level. are satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? 0.35 versus H,: p < 0.35 Ho: p (Type integers or decimals. Do not round.) Find the test statistic, zo- Z, = - 1.26 (Round to two decimal places as needed.) Find the P-value. P-value = (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. Check Answer 1 Clear All 1 part remainina
Of 100 students, 27 can speak French F, 36 can speak German G, and 14 can speak both French and German. How many students speak neither French nor German? Oa. 49 O b.35 O c. 51 Od. 63 O e. 14
A set of data was published in the fall 2019 Phi Kappa Phi Forum regarding the performance of Major League Baseball (MLB) umpires in calling balls and strikes. The article is based on data collected by MLB over eleven seasons (2008-2018). This study shows that it is common for umpires to make incorrect calls more than 20% of the time. An average game has about 300 pitches where the umpire has to make a decision. Assume that we take a random sample of 300 of the 4 million ball/strike calls in the database. Our analysis of a new sample yielded a Z test statistic of 2.17 for this one-sided test to the right. The p-value is = .015. Make a decision on this hypothesis test using a 5% level of significance and state the reason for your decision. O Reject the null hypothesis since the p-value is .01
In a previous poll, 3,1% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 1199 adults with children under the age of 18 were selected at random, and 350 of those 1199 adults reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use the α = 0.05 significance level > 10 and the sample size is less than 5% of the population size, and the adults in the sample Because npo (1-Po) = 256.5 hypothesis are satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? ₹ 31 Ho р 31 versus H₁: = р (Type integers or decimals. Do not round.) Find the test statistic, Zo Zo= (Round to two decimal places as needed) were selected at random, all of the requirements for testing the
The National Academy of Science reported that 41% of research in mathematics is published by US authors. The mathematics chairperson of a prestigious university wishes to test the claim that this percentage is no longer 41%. He has no indication of whether the percentage has increased or decreased since that time. He surveys a simple random sample of 186 recent articles published by reputable mathematics research journals and finds that 92 of these articles have US authors. Does this evidence support the mathematics chairperson’s claim that the percentage is no longer 41%? Use a 0.05 level of significance. Step 1 of 3: State the null and alternative hypotheses for the test. circle the answer below. H0 p=0.41 ha: p⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯0.41 A.<B.≠C.> Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places Step 3 of 3: Draw a conclusion and interpret the decision. A. We reject the null hypothesis and conclude that there is insufficient evidence at a…
According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 320 community college students at random and finds that 135 of them have a smart phone. In testing the hypotheses: Ho: p = 0.33 versus Ha: p > 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for #3 and #4. 1. This is an example of a hypothesis test. 2. Find the standard error. 3. Find the z value. 4. Find the p-value. 5. The communication professor should the null hypothesis.
In a previous poll, 38% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 1186 adults with children under the age of 18 were selected at random, and 428 of those 1186 adults reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use the α = 0.01 significance level. Because npo (1-Po) = 279.4 > 10 and the sample size is (Round to one decimal place as needed.) What are the null and alternative hypotheses? но: р = 0.38 versus H₁: p (Type integers or decimals. Do not round.) Find the test statistic, Zo. < 0.38 Zo -1.36 (Round to two decimal places as needed.) = Find the P-value. P-value = (Round to three decimal places as needed.) less than 5% of the population size, and the adults in the sample were selected at random, all of…
The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,476 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 153 of their customers and calculates that these customers used an average of 10,767 kWh of electricity last year. Assuming that the population standard deviation is 2478 kWh, is there sufficient evidence to support the power company's claim at the 0.05 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.
The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,941 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 115 of their customers and calculates that these customers used an average of 11,425 kWh of electricity last year. Assuming that the population standard deviation is 3217 kWh, is there sufficient evidence to support the power company's claim at the 0.02 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.
The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,069 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 171 of their customers and calculates that these customers used an average of 10,461 kWh of electricity last year. Assuming that the population standard deviation is 2973 kWh, is there sufficient evidence to support the power company's claim at the 0.01 level of significance? Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.