A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Men Women μ μ1 μ2 n 11 59 x 97.72 degrees°F 97.39degrees °F s 0.88 degrees°F 0.68 degrees °F a. Use a 0.05 0.05 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? A. Upper H 0 H0: mu 1 μ1 equals = mu 2 μ2 Upper H 1 H1: mu 1 μ1 not equals ≠ mu 2 μ2 B. Upper H 0 H0: mu 1 μ1 greater than or equals ≥ mu 2 μ2 Upper H 1 H1: mu 1 μ1 less than < mu 2 μ2 C. Upper H 0 H0: mu 1 μ1 not equals ≠ mu 2 μ2 Upper H 1 H1: mu 1 μ1 less than < mu 2 μ2 D. Upper H 0 H0: mu 1 μ1 equals = mu 2 μ2 Upper H 1 H1: mu 1 μ1 greater than > mu 2 The test statistic, t, is ___ The P-value is ____ State the conclusion for the test. A. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. B. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. C. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. D.Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. b. Construct a confidence interval suitable for testing the claim that males and females have the same mean BMI. ___< μ1 - μ2<___ (Round to three decimal places as needed.) Does the confidence interval support the conclusion of the test? _____ because the confidence interval contains____

A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Men Women μ μ1 μ2 n 11 59 x 97.72 degrees°F 97.39degrees °F s 0.88 degrees°F 0.68 degrees °F a. Use a 0.05 0.05 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? A. Upper H 0 H0: mu 1 μ1 equals = mu 2 μ2 Upper H 1 H1: mu 1 μ1 not equals ≠ mu 2 μ2 B. Upper H 0 H0: mu 1 μ1 greater than or equals ≥ mu 2 μ2 Upper H 1 H1: mu 1 μ1 less than < mu 2 μ2 C. Upper H 0 H0: mu 1 μ1 not equals ≠ mu 2 μ2 Upper H 1 H1: mu 1 μ1 less than < mu 2 μ2 D. Upper H 0 H0: mu 1 μ1 equals = mu 2 μ2 Upper H 1 H1: mu 1 μ1 greater than > mu 2 The test statistic, t, is _ The P-value is State the conclusion for the test. A. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. B. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. C. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. D.Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. b. Construct a confidence interval suitable for testing the claim that males and females have the same mean BMI. _< μ1 - μ2<_ (Round to three decimal places as needed.) Does the confidence interval support the conclusion of the test? _ because the confidence interval contains__

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

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A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below.		Men	Women
	μ	μ1	μ2
	n	11	59
	x	97.72 degrees°F	97.39degrees °F
	s	0.88 degrees°F	0.68 degrees °F

a. Use a

0.05

0.05 significance level to test the claim that men have a higher mean body temperature than women.

What are the null and alternative hypotheses?

Upper H 0

H0:

mu 1

μ1

equals

mu 2

μ2

Upper H 1

H1:

mu 1

μ1

not equals

≠

mu 2

μ2

Upper H 0

H0:

mu 1

μ1

greater than or equals

≥

mu 2

μ2

Upper H 1

H1:

mu 1

μ1

less than

mu 2

μ2

Upper H 0

H0:

mu 1

μ1

not equals

≠

mu 2

μ2

Upper H 1

H1:

mu 1

μ1

less than

mu 2

μ2

Upper H 0

H0:

mu 1

μ1

equals

mu 2

μ2

Upper H 1

H1:

mu 1

μ1

greater than

mu 2

The test statistic, t, is ___

The P-value is ____

State the conclusion for the test.

A. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI.

B. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI.

C. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI.

D.Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI.

b. Construct a confidence interval suitable for testing the claim that males and females have the same mean BMI.

___< μ1 - μ2<___

(Round to three decimal places as needed.)

Does the confidence interval support the conclusion of the test?

_____ because the confidence interval contains____

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Expert Solution

Step 1

(a)

State the hypotheses.

Correct option: Option D

Obtain the value of the test statistic.

The value of the test statistic is obtained below as follows :

Thus, the value of the test statistic is 1.18.

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