Question content area topPart 1A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. MenWomen μμ1μ2n1159x97.54°F97.46°Fs0.95°F0.63°F Question content area bottomPart 1a. Use a0.01significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? A.H0:μ1=μ2H1:μ1≠μ2 B.H0:μ1≠μ2H1:μ1<μ2 C.H0:μ1=μ2H1:μ1>μ2Your answer is correct. D.H0:μ1≥μ2H1:μ1<μ2Part 2The test statistic, t, isenter your response here.(Round to two decimal places as needed.)

From the provided information, n1=11x1=97.54s1=0.95n2=59x2=97.46s2=0.63Part 1 The claim is that men have a higher mean body temperature than women. The hypotheses for the claim can be constructed as: H0: μ1 = μ2 H1: μ1 > μ2 The correct option is C).Part 2 The value of test statistic can be obtained as: t=x1-x2s12n1+s22n2=97.54-97.460.95211+0.63259=0.27 Thus, the required test statistic is 0.27.

Answered: A study was done on body temperatures…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question content area top

Part 1

A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below.			Men	Women
μ	μ1	μ2
n	11	59
x	97.54°F	97.46°F
s	0.95°F	0.63°F

Question content area bottom

Part 1

a. Use a

0.01

significance level to test the claim that men have a higher mean body temperature than women.

What are the null and alternative hypotheses?

H0:

μ1=μ2

H1:

μ1≠μ2

H0:

μ1≠μ2

H1:

μ1<μ2

H0:

μ1=μ2

H1:

μ1>μ2

Your answer is correct.

H0:

μ1≥μ2

H1:

μ1<μ2

Part 2

The test statistic, t, is

enter your response here.

(Round to two decimal places as needed.)

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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