A study reports the following data on impregnated compressive modulus (psi ✕ 106) when two different polymers were used to repair cracks in failed concrete. Epoxy 1.74 2.13 2.03 1.96 MMA prepolymer 1.79 1.56 1.71 1.68 Obtain a 90% CI for the ratio of variances by first using the method suggested below to obtain a general confidence interval formula. (Use s1 for expoxy and s2 for MMA prepolymer. Round your answers to two decimal places.) 0.32 Incorrect: Your answer is incorrect. , 27.90 Incorrect: Your answer is incorrect. P F1−?/2,m−1,n−1 ≤ S12/?12 S22/?22 ≤ F?/2,m−1,n−1 = 1 − ? You may need to use the appropriate table in the Appendix of Tables to answer this question.

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.4 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use a = 0.05.) State the appropriate hypotheses. O H,: H 48 H:u = 48 O H,: = 48 Hi u 48 OH:= 48 H: u + 48 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) P-value = What can you conclude? O The data provides compelling…

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.3 and the sample standard deviation was 1.4. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.) State the appropriate hypotheses. ⒸH₂: μ = 48 Ha: > 48 Ho:μ = 48 H₂H 48 H₂: μ = 48 Ho: μ< 48 H₂₁:μ = 48 USE SALT Ho: M = 48 H₂:48 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t= 7.68 X P-value =

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.3. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.) USE SALT State the appropriate hypotheses. ⒸHO: μ> 48 H₂: μ = 48 Ho: μ 48 Ho: μ = 48 H₂: μ = 48 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t = P-value = What can you conclude? O The data provides compelling…

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.4 and the sample standard deviation was 1.5. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.) Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t  =    P-value  =

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.8 and the sample standard deviation was 1.5. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use a = 0.05.) n USE SALT State the appropriate hypotheses. Ho:H = 48 Ha:µ > 48 = 48 Hạ: u + 48 Ho: H = 48 Hai u 48 H: µ = 48 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t = P-value = What can you conclude? O The data…

A 95% confidence interval for the variance of a normal data of size 10 was obtained as [3.5, 24.3] find the value of sr if Xn-1a/2=19.0 and x-11-a/2=2.7 = 2.7 O A. 7.3 оВ. 11.7 O C. 2.7 O D. 3.4 O E. None of these

Use the information from a simple linear regression given in the table below to calculate a 95% confidence interval for B1. SSXY = 285.2 SSXX = 23 S = 7 n = 15 Beta0 hat = 36 Betal hat = 12.4 O (25.78, 46.22) O (11.50, 13.29) O (- 9.67, 34.47) O (9.25, 15.55)

A manufacturer bonds a plastic coating to a metal surface. A random sample of nine observations on the thickness of this coating is taken from a week's output and the thickness (in millimeters) of these observations are shown below. Assuming normality, find a 90 % confidence interval for the population variance. 19.7 20.5 Click the icon to view a table of lower critical values for the chi-square distribution. Click the icon to view a table of upper critical values for the chi-square distribution. 21.8 18.2 Find the 90% confidence interval. 0<²0 (Round to four decimal places as needed.) 21.6 SCIOD 19.3 19.7 20.2 20.7

Researchers measured the occurrence of reptiles using pitfall trapping across mallee Eucalyptus habitats that had been either recently burnt or unburnt. They were interested in comparing the abundance Southern knob-tail geckos (Nephrurus stellatus) between these two habitats and so calculated the relative abundance of this species found at each trap. Based on the output below, what would be the most correct conclusion to draw about these data?         Mean n Std deviation Std error of mean burnt sites 8.08 30 6.12 0.94 unburnt sites 2.73 30 3.33 0.51   Variance ratio test = 3.37 : 1    options:   The data are skewed and a log transformation (after adding 10 too all values to remove negative and zero values) should be attempted before performing a parametric test   The data are skewed, however a transformation would not be appropriate for these data   The data are symmetrical, a parametric test…