A study of the career paths of hotel general managers sent questionnaires to a random sample of 280 hotels belonging to major U.S. hotel chains. There were 169 responses. The average time these 169 general managers had spent with their current company was 11.05 years, and the standard deviation of time with the company was 2.6 years. (a) Find the margin of error for a confidence interval to estimate the mean time a general manager had spent with their current company. Use a confidence level of 90%.     Answer: years (b) Find the margin of error for a confidence interval to estimate the mean time a general manager had spent with their current company. Use a confidence level of 99%.

Q: Of 500 random people surveyed, 72 were smokers.  Find the 95% confidence interval. SE=0.0157

A:

Q: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The…

A: Here we need to construct an 80% CI for the mean amount of money spent on child's last birthday…

Q: A study of the career paths of hotel general managers sent questionnaires to an SRS of 300 hotels…

A:

Q: 2. A recent study of 25 students showed that they spent on average of $18.35 for gasoline per week.…

A: Given  x̄ = 18.35 n=25 s=3 degree of freedom = df = n -1 = 25-1 = 24 significance level α = 0.10…

Q: A poll reported that only 507 out of a total of 1809 adults in a particular region said they had a​…

A: The sampled no. of adults, i.e., the sample size, n=1809. The no. of sampled adults who expressed a…

Q: A car repair business randomly selects receipts for parts purchased on 16 different jobs. The mean…

A: given data, n=16x¯=31.32s=30.42CI=0.95α=1-0.95=0.05df=n-1=16-1=15we  have to construct the 95%…

Q: A study of 40 English composition professors showed that they​ spent, on​ average, 12.6 minutes…

A:

Q: In a survey, 45 people were asked how much they spent on their last partners birthday gift. The…

A: Given information- Sample size, n = 45 Significance level, α = 0.10 Sample mean, x-bar = $90 Sample…

Q: Heather runs a successful lawn-mowing business. She would like to estimate the true mean amount of…

A: Given that  Sample size n =30 90 % confidence interval is (40 , 55)

Q: sample of 16 students was taken from university. These students spent an average of $170 on books…

A:

Q: To study the perceptions of waiting time, a researcher conducted a survey of 100 prospective…

A: The provided information  x¯=5.2σ=1.2n=100α=0.10The critical value is zc=1.64  (from statistical…

Q: A study was commissioned to find the mean weight of the residents in certain town. The study…

A: Given: n=58, x=174 and s=38. Now,Degrees of freedom=n-1=58-1=57 Then, at 95% confidence level, the…

Q: The 90% confidence interval is from to. (Round to three decimal places as needed.)

A: A poll of 1030 adults in a country was conducted by telephone. Of those surveyed, 139 had…

Q: A random sample of 110 Americans was asked how many hot dogs they eat each year.  The sample mean…

A:

Q: 2. In a recent study of 35 college students, the mean number of hours per week that they played…

A: According to the given information in this question  We need to find the 95% confidence interval

Q: A marketing researcher wants to estimate the mean savings ($) realized by shoppers who showroom.…

A: Sample size Sample mean Sample standard deviation

Q: Suppose we are contracted by the Justice Department to study the extent of juvenile delinquency.  We…

A:

Q: C. Find a 95% confidence interval for the average life time of all the television sets produced by a…

A:

Q: In Oct. 2008, scientists tested cord blood samples for 20 newborn infants in USA. The scientists…

A: Given information- Sample size, n = 20 Now, degree of freedom is given by- Degree of freedom, df = n…

Q: A study of 64 bolts of carpet showed that their average length was 75 yards. The standard deviation…

A:

Q: The 95​% confidence interval for the proportion that express a great deal of confidence or quite a…

A: A poll reported that only 645 out of a total of 2029 adults in a particular region said they had a​…

Q: Do people walk faster in the airport when they are departing or when they are arriving? Researchers…

A: given data departing travellers:x¯1  = 256s1 = 31n1 = 45arriving travellersx¯2  =241s2 = 58n2 =…

Q: A student organization conducted a statistical study to calculate a 95% confidence interval for the…

A: Hence,

Q: Scott wants to find a 95% confidence interval for the average GPA for Allegany College of Maryland…

A:

Q: A sociologist develops a test to measure attitudes about public transportation, and 20 randomly…

A: The confidence interval is a set of elements that have been imagined to comprise, with a specified…

Q: 73 full time workers were surveyed on how many hours they spend watching television during the week.…

A: Given information, n=73x¯=3.2s=0.2 Confidence level is 95% significance level is 5% df=n-1=73-1=72 t…

Q: A medical researcher surveyed 9 hospitals and found that the standard deviation for the cost for…

A:

Q: In a survey of 3332 adults aged 57 through 85​ years, it was found that 80.7​% of them used at least…

A:

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A: Given information- Sample size, n = 14 Mean, x-bar = $32 Standard deviation, s = $20 Confidence…

Q: A study of the career paths of hotel general managers sent questionnaires to an simple random sample…

A: Given information Standard deviation σ = 1.5 Sample size, n = 280 Confidence level = 0.80…

Q: company manufactures a certain over-the-counter drug. The company samples 80 pills and finds that…

A: We have given that  Sample size n = 80 Sample mean = 325.5 Standard deviation s=10.3 90%confidence…

Q: A study of 100 patients with back pain reported that the mean duration of pain was 12 months. It is…

A: In question, Given that a study of 100 patients with back pain reported that the mean duration of…

Q: sample of seven laptop computers had a variance of 25.88 years when the lifespan of the computer was…

A:

Q: To determine the views of students on a particular campus about fraternities, an 11-point attitude…

A:

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Q: In a study, 110 children of a certain race in a certain city were randomly assigned to one of two…

A: There are two independent samples which are Preschool and No Preschool. We have to construct 95%…

Q: A researcher is interested in finding a 98% confidence interval for the mean number of times per day…

A:

Q: A researcher is attempting to calculate a 95% confidence interval for the mean average wingspan of…

A: The random variable wingspan follows normal distribution. We have to find the 95% confidence…

Q: A sample of 30 days of sales were taken. The mean of those 30 days of sales were $10,000 with a…

A: Given values, sample size (n) = 30 Mean = 10,000 Standard deviation = 2000 z value for 95%…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.