A study of the ability of individuals to walk in a straight line reported the accompanying data on cadence (strides per second) for a sample of n = 20 randomly selected healthy men.0.93 0.85 0.92 0.95 0.93 0.86 1.00 0.92 0.85 0.810.78 0.93 0.93 1.02 0.93 1.06 1.06 0.96 0.81 0.98Assume the population distribution of cadence is approximately normal. A descriptive summary of the data is as follows:VariablecadenceVariablecadenceN20Mean0.9240Min0.7800Median0.9300Max1.0600St Dev0.0792Q10.8550Q30.9700(a) Calculate and interpret a 95% confidence interval for population mean cadence. (Round your answers to four decimal places.)strides per secondInterpret this interval.With 95% confidence, the value of the true mean cadence of all such men falls within the confidence interval.The probability the true mean cadence is within this interval is 0.95.With 95% confidence, the value of the true mean cadence of all such men falls above the confidence interval.With 95% confidence, the value of the true mean cadence of all such men falls below the confidence interval.

The sample size of healthy men selected using random selection, Provided data on cadence:The…

Answered: A study of the ability of individuals…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The histogram of the number of hours of sleep Stat 100 students reported getting each night roughly follows the normal curve with an average of 7.0 hours and a SD of 1.2 hours. a. Approximately 68% of the students sleep between hours and hot (Put the smaller number first) 提交答案|Tries 0/5 b. Approximately 95% of the students sleep between hours and hours. (Put the smaller number first) 提交答案| Tries 0/5 c. If a student sleeps 5.2 hours per night what percent of the people sleep more than her? Do the problem in steps: I. First, find the Z score = 提交答案|Tries 0/3 ii. Now, move the red vertical line on the following graph to the correct Z score by clicking and dragging the mouse. If you are using a touch screen, touch and then slide the region around the vertical line 1.00 Shade the region representing the percent of people who sleep more than her: Shade the region under the normal curve to the O left of the red vertical line O right of the red vertical line
Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15.
Answer the question in the second photo with the data provided in the first photo
The table available below shows the weights (in pounds) for a sample of vacuum cleaners. The weights are classified according to vacuum cleaner type. At a = 0.10, can you conclude that at least one mean vacuum cleaner weight is different from the others? Click the icon to view the vacuum cleaner weight data. Let μBU, BLU, and μTC represent the mean weights for bagged upright, bagless upright, and top canister vacuums respectively. What are the hypotheses for this test? A. Ho: At least one of the means is different. Ha: MBUHBLUPTC B. Ho: "BU HBLU HTC # Ha: MBUHBLUPTC C. Ho: MBUHBLU = HTC Ha: At least one of the means is different. D. Ho: MBU - HBLU = μTC Ha: HBU #BLU HTC What is the test statistic? F = 12.56 (Round to two decimal places as needed.) What is the P-value? P-value = 0.000624 (Round to three decimal places as needed.)
Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15.
Refer to the figure at the right. At a= 0.10, can you reject the claim that the proportion of 18 to 24-year-olds living in their parents' homes in 2000 was the same for men and women? Assume the survey included a random sample of 270 men and 278 women. Percentage of 18- to 24-year olds living in parents' homes 70, 60.4% 45% 54.6% 50.3% 2000 2012 Men Women Identify the null and alternative hypotheses. Choose the correct answer below. O B. Ho: P, * P2 Ha: P1 = P2 OD. Ho: P1 > P2 YA. Ho: P1 = P2 H3: P, * P2 OC. Ho: P, P2 Ha: P, SP2 Find the critical value(s). The critical value(s) is(are). (Round to two decimal places as needed. Use a comma to separate answers as needed.)
Calcium levels in people are normally distributed with a mean of 9.7 mgdL and a standard deviation of 0.5 mgdL . Individuals with calcium levels in the bottom 10% of the population are considered to have low calcium levels. Find the calcium level that is the borderline between low calcium levels and those not considered low. Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
The goal of the one-sample t-test is to: Group of answer choices describe the location of a score within a distribution compare the mean of a sample to the population mean. compare the means of two samples. compare the standard deviation of a sample to the standard deviation of the population.
Assume the cholesterol levels of an adult can be described by a Normal model with a mean of 183 mg/dL and a standard deviation of 27. Complete parts a through e. b) What percent of adults do you expect to have cholesterol levels over 190 mg/dL? enter your response here % (Round to two decimal places as needed.) Part 3 c) What percent of adults do you expect to have cholesterol levels between 150 and 160 mg/dL? enter your response here % (Round to two decimal places as needed.) Part 4 d) Estimate the interquartile range of cholesterol levels. IQR=enter your response here mg/dL (Round to the nearest integer as needed.) Part 5 e) Above what value are the highest 15% of adults' cholesterol levels? enter your response here mg/dL (Round to the nearest integer as needed.)
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A manufacturer of light bulbs finds that one light bulb model has a mean life span of 1025 h with a standard deviation of 83 h.Find the z-scores for lightbulbs which last 850 and 900 h. (Round your answers to two decimal places.) 850 h: z = 900 h: z =
Indicate whether 25 is sufficient or whether a sample of 50 would be necessary. You will want to calculate the probability of the sample mean being between $11,000 and $13,000 for both a sample size of 25 and 50. (Thank You!)

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