A study has been made to compare the nicotine contents of two brands of cigarettes. 5 cigarettes of Brand A had an average nicotine content of 4.3 milligrams with a standard deviation of 0.5 milligram, while eight cigarettes of Brand B had an average nicotine content of 2.7 milligrams with a standard deviation of 0.7 milligram. Assuming that the two sets of data are independent random samples from normal popuiations with equal variances, construct a 95% confidence interval for the difference between the mean nicotine contents of the two brands of cigarettes.

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
icon
Related questions
Question
**Comparison of Nicotine Contents in Cigarettes: A Statistical Approach**

In a recent study, researchers aimed to compare the nicotine contents of two different brands of cigarettes. They examined the following data:

- **Brand A**: Five cigarettes were tested, revealing an average nicotine content of 4.3 milligrams with a standard deviation of 0.5 milligrams.
- **Brand B**: Eight cigarettes were tested, showing an average nicotine content of 2.7 milligrams with a standard deviation of 0.7 milligrams.

The objective was to determine a 95% confidence interval for the difference in mean nicotine contents between the two brands. The study assumes the following:

- The data sets for each brand are independent random samples.
- The populations are normally distributed with equal variances.

This analysis helps in understanding if there is a significant difference in nicotine content between the two brands of cigarettes.
Transcribed Image Text:**Comparison of Nicotine Contents in Cigarettes: A Statistical Approach** In a recent study, researchers aimed to compare the nicotine contents of two different brands of cigarettes. They examined the following data: - **Brand A**: Five cigarettes were tested, revealing an average nicotine content of 4.3 milligrams with a standard deviation of 0.5 milligrams. - **Brand B**: Eight cigarettes were tested, showing an average nicotine content of 2.7 milligrams with a standard deviation of 0.7 milligrams. The objective was to determine a 95% confidence interval for the difference in mean nicotine contents between the two brands. The study assumes the following: - The data sets for each brand are independent random samples. - The populations are normally distributed with equal variances. This analysis helps in understanding if there is a significant difference in nicotine content between the two brands of cigarettes.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability
A First Course in Probability
Probability
ISBN:
9780321794772
Author:
Sheldon Ross
Publisher:
PEARSON