A study finds that the carapace length of an adult spider is normally distributed with a mean of 17.55 mm and a standard deviation of 1.42 mm. Let x denote carapace length for the adult spider. a. Sketch the distribution of the variable x. Choose the correct graph below. O A. B. C. -51 -34 1.42 37 54 13 15 17.55 20 22 b. Obtain the standardized version, z, of x. Choose the correct standardized version below. O A. (x- 17.55) Z= ов. (z- 17.55) 1.42 1.42 OC. (z - 1.42) D. (x - 1.42) 17.55 17.55 c. Identify and sketch the distribution of z. Choose the correct graph below. O A. ов. OC. 13 15 17.55 20 22 -2 -1 -2 d. Find the z-scores that correspond to the percentage of adult spiders that have carapace lengths between 16 mm and 17 mm. The percentage of adult spiders that have carapace lengths between 16 mm and 17 mm is equal to the area under the standard normal curve between (Round to two decimal places as needed.) and e. Find the z-score and direction that corresponds to the percentage of adult spiders that have carapace lengths exceeding 20 mm. The percentage of adult spiders that have carapace lengths exceeding 20 mm is equal to the area under the standard normal curve that lies to the right of. (Round to two decimal places as needed.)

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Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.