A student working in the physics laboratory connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 225 V. Assume a plate separation of d = 1.41 cm and a plate area of A = 25.0 cm the battery is removed, the capacitor is plunged into container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) Q, = 353 Q = 353 before v pC v PC after (b) Determine the capacitance (in F) and potential difference (in V) after immersion. 126 X F AV = 281 (c) Determine the change in energy (in nJ) of the capacitor. AU = 39.3 x n) (d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 225 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q, = 353 V pC v pC after Q = 28242 Determine the capacitance (in F) and potential difference (in V) after immersion. 125 X F AV = 225 Determine the change in energy (in n) of the capacitor.
A student working in the physics laboratory connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 225 V. Assume a plate separation of d = 1.41 cm and a plate area of A = 25.0 cm the battery is removed, the capacitor is plunged into container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) Q, = 353 Q = 353 before v pC v PC after (b) Determine the capacitance (in F) and potential difference (in V) after immersion. 126 X F AV = 281 (c) Determine the change in energy (in nJ) of the capacitor. AU = 39.3 x n) (d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 225 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q, = 353 V pC v pC after Q = 28242 Determine the capacitance (in F) and potential difference (in V) after immersion. 125 X F AV = 225 Determine the change in energy (in n) of the capacitor.
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P555
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Part(b)
Part(c)
Part(d) - Cf
Transcribed Image Text:A student working in the physics laboratory connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 225 V. Assume a plate separation of d = 1.41 cm and a plate area of A = 25.0 cm2. When
the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0.
(a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before
Q;
353
pC
after
Qf =
353
pC
(b) Determine the capacitance (in F) and potential difference (in V) after immersion.
X F
Cf
AV = 2.81
126
V
(c) Determine the change in energy (in n)) of the capacitor.
AU = 39.3
X nJ
(d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 225 V potential difference.
Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before
= 353
Q;
Qf
V pC
after
28242
pC
%3D
Determine the capacitance (in F) and potential difference (in V) after immersion.
Cf = 125
X F
AVF = 225
Determine the change in energy (in nJ) of the capacitor.
AU = 3137
nJ
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