A student was given a white powdered solid unknown sample mixture made-up of sodium carbonate and sodium hydroxide. He took 0.3721 g of dissolved in 250.0 mL distilled water. In each trial he took 50.00 mL of unknown sample solution and conducted double titration as shown in the videos against 0.1000 M HCl. He did 5 trials and his results are given below: Trial V1 (mL) V2 (mL) 1 10.00 2.00 2 3 4 5 Calculate % NaOH and % Na2CO3 for trial#1.
A student was given a white powdered solid unknown sample mixture made-up of sodium carbonate and sodium hydroxide. He took 0.3721 g of dissolved in 250.0 mL distilled water. In each trial he took 50.00 mL of unknown sample solution and conducted double titration as shown in the videos against 0.1000 M HCl. He did 5 trials and his results are given below: Trial V1 (mL) V2 (mL) 1 10.00 2.00 2 3 4 5 Calculate % NaOH and % Na2CO3 for trial#1.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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I need help solving the problems with these equations:
A student was given a white powdered solid unknown sample mixture made-up of sodium carbonate and sodium hydroxide. He took 0.3721 g of dissolved in 250.0 mL distilled water. In each trial he took 50.00 mL of unknown sample solution and conducted double titration as shown in the videos against 0.1000 M HCl. He did 5 trials and his results are given below:
Trial | V1 (mL) | V2 (mL) |
1 | 10.00 | 2.00 |
2 | ||
3 | ||
4 | ||
5 |
Calculate % NaOH and % Na2CO3 for trial#1.

Transcribed Image Text:% Na₂CO3 =
V(CO3-²)
((2xV₂) x N x f)HCI X meq Na₂CO3
V sample
meq Na₂CO3 =
Pm Na₂CO3/nº H+
1000
X 100
106/2
1000
= 0.053

Transcribed Image Text:% NaOH =
V(OH-)
||
((V₁-V₂) × N x f)µ¤ × meq NaOH
V sample
meq de NaOH =
Pm NaOH/nº OH-
1000
X 100
40/1
1000
= 0.04
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