A student used 9.925 x 10-2 mol/L hydrobromic acid to standardize an aqueous solution of potassium hydroxide and obtained the following titration data using phenolphthalein as an indicator: Concentration of HBr used: 9.925 x 10-2 mol/L Volume of HBr used: 25.00 mL Indicator: phenolphthalein Endpoint colour change: colorless to pale pink Table 1: Volume of Potassium Hydroxide Required Burette reading (mL) Trial 1 Trial 2 Trial 3 Final reading 29.28 36.62 43.98 Initial reading 1.78 9.28 16.62 Volume of KOH used (mL) Average of 2 closest values to within 0.10 mL: Questions Complete Inclosed table Write the molecular equation for the reaction that occurs between potassium hydroxide and hydrobromic acid. Calculate the molar concentration, in mol/L, of the aqueous potassium hydroxide.

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A student used 9.925 x 10-2 mol/L hydrobromic acid to standardize an aqueous solution of potassium hydroxide and obtained the following titration data using phenolphthalein as an indicator: Concentration of HBr used: 9.925 x 10-2 mol/L Volume of HBr used: 25.00 mL Indicator: phenolphthalein Endpoint colour change: colorless to pale pink Table 1: Volume of Potassium Hydroxide Required Burette reading (mL) Trial 1 Trial 2 Trial 3 Final reading 29.28 36.62 43.98 Initial reading 1.78 9.28 16.62 Volume of KOH used (mL) Average of 2 closest values to within 0.10 mL: Questions Complete Inclosed table Write the molecular equation for the reaction that occurs between potassium hydroxide and hydrobromic acid. Calculate the molar concentration, in mol/L, of the aqueous potassium hydroxide.
Table 1: Volume of Potassium Hydroxide Required
Burette reading (mL)
Trial 1
Trial 2
Trial 3
Final reading
Initial reading
Volume of KOH used (mL)
36.62
9.28
29.28
43.98
1.78
16.62
Average of 2 closest values to within 0.10 mL:
Transcribed Image Text:Table 1: Volume of Potassium Hydroxide Required Burette reading (mL) Trial 1 Trial 2 Trial 3 Final reading Initial reading Volume of KOH used (mL) 36.62 9.28 29.28 43.98 1.78 16.62 Average of 2 closest values to within 0.10 mL:
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