A student ran the following reaction in the laboratory at 671 K: H₂(g) + 12 (9) 2HI(g) When she introduced 0.191 moles of H₂(g) and 0.214 moles of 12 (g) into a 1.00 liter container, she found the equilibrium concentration of 12 (9) to be 0.0545 M. Calculate the equilibrium constant, Ko, she obtained for this reaction. Ke=

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A student ran the following reaction in the laboratory at 671 K:
H₂ (9) + I2(g) → 2HI(g)
When she introduced 0.191 moles of
H₂(g) and 0.214 moles of
1₂ (g) into a 1.00 liter container, she found the equilibrium concentration of
12 (g) to be 0.0545 M.
Calculate the equilibrium constant, Ke, she obtained for this reaction.
Ke=
Transcribed Image Text:A student ran the following reaction in the laboratory at 671 K: H₂ (9) + I2(g) → 2HI(g) When she introduced 0.191 moles of H₂(g) and 0.214 moles of 1₂ (g) into a 1.00 liter container, she found the equilibrium concentration of 12 (g) to be 0.0545 M. Calculate the equilibrium constant, Ke, she obtained for this reaction. Ke=
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