A student produced 347 mL of hydrogen gas at -37.5 °C and constan temperature (°C) will this gas expand to a volume of 750 mL?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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### Gas Laws in Action: Temperature and Volume Relationship

**Problem Statement:**
A student produced 347 mL of hydrogen gas at -37.5 °C and constant atmospheric pressure. At what temperature (°C) will this gas expand to a volume of 750 mL?

**Solution Approach:**
To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin) when pressure is constant. 

**Charles's Law Formula:**

\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]

Where:
- \( V_1 \) is the initial volume of the gas (347 mL),
- \( T_1 \) is the initial temperature (in Kelvin),
- \( V_2 \) is the final volume of the gas (750 mL),
- \( T_2 \) is the final temperature (in Kelvin).

**Converting Temperatures to Kelvin:**
- Initial temperature \( T_1 \):
  \[ T_1 = -37.5 °C + 273.15 = 235.65 \text{ K} \]
  
**Setting Up the Equation:**
\[
\frac{347}{235.65} = \frac{750}{T_2}
\]

**Solving for \( T_2 \):**
\[
T_2 = \frac{750 \times 235.65}{347}
\]

**Converting Back to Celsius:**
After calculating \( T_2 \) in Kelvin, convert it back to Celsius by subtracting 273.15. 

**Graphical Explanation:**
If a graph were provided, it would typically show the direct relationship between Temperature (x-axis) and Volume (y-axis). The line should ideally be straight, illustrating the linearity between the two variables as per Charles's Law. 

**Answer Box:**
An input field for students to enter their calculated temperature in Celsius.

By solving this equation, students will gain a deeper understanding of the direct proportionality between the volume and temperature of a gas under constant pressure.
Transcribed Image Text:### Gas Laws in Action: Temperature and Volume Relationship **Problem Statement:** A student produced 347 mL of hydrogen gas at -37.5 °C and constant atmospheric pressure. At what temperature (°C) will this gas expand to a volume of 750 mL? **Solution Approach:** To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin) when pressure is constant. **Charles's Law Formula:** \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] Where: - \( V_1 \) is the initial volume of the gas (347 mL), - \( T_1 \) is the initial temperature (in Kelvin), - \( V_2 \) is the final volume of the gas (750 mL), - \( T_2 \) is the final temperature (in Kelvin). **Converting Temperatures to Kelvin:** - Initial temperature \( T_1 \): \[ T_1 = -37.5 °C + 273.15 = 235.65 \text{ K} \] **Setting Up the Equation:** \[ \frac{347}{235.65} = \frac{750}{T_2} \] **Solving for \( T_2 \):** \[ T_2 = \frac{750 \times 235.65}{347} \] **Converting Back to Celsius:** After calculating \( T_2 \) in Kelvin, convert it back to Celsius by subtracting 273.15. **Graphical Explanation:** If a graph were provided, it would typically show the direct relationship between Temperature (x-axis) and Volume (y-axis). The line should ideally be straight, illustrating the linearity between the two variables as per Charles's Law. **Answer Box:** An input field for students to enter their calculated temperature in Celsius. By solving this equation, students will gain a deeper understanding of the direct proportionality between the volume and temperature of a gas under constant pressure.
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