Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Gas Laws in Action: Temperature and Volume Relationship
**Problem Statement:**
A student produced 347 mL of hydrogen gas at -37.5 °C and constant atmospheric pressure. At what temperature (°C) will this gas expand to a volume of 750 mL?
**Solution Approach:**
To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin) when pressure is constant.
**Charles's Law Formula:**
\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]
Where:
- \( V_1 \) is the initial volume of the gas (347 mL),
- \( T_1 \) is the initial temperature (in Kelvin),
- \( V_2 \) is the final volume of the gas (750 mL),
- \( T_2 \) is the final temperature (in Kelvin).
**Converting Temperatures to Kelvin:**
- Initial temperature \( T_1 \):
\[ T_1 = -37.5 °C + 273.15 = 235.65 \text{ K} \]
**Setting Up the Equation:**
\[
\frac{347}{235.65} = \frac{750}{T_2}
\]
**Solving for \( T_2 \):**
\[
T_2 = \frac{750 \times 235.65}{347}
\]
**Converting Back to Celsius:**
After calculating \( T_2 \) in Kelvin, convert it back to Celsius by subtracting 273.15.
**Graphical Explanation:**
If a graph were provided, it would typically show the direct relationship between Temperature (x-axis) and Volume (y-axis). The line should ideally be straight, illustrating the linearity between the two variables as per Charles's Law.
**Answer Box:**
An input field for students to enter their calculated temperature in Celsius.
By solving this equation, students will gain a deeper understanding of the direct proportionality between the volume and temperature of a gas under constant pressure.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19b0aed3-745e-4879-8577-ea35399669d0%2Fdcd50ccc-de21-45db-95f2-203dc410dbef%2Fn3v2hhi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Gas Laws in Action: Temperature and Volume Relationship
**Problem Statement:**
A student produced 347 mL of hydrogen gas at -37.5 °C and constant atmospheric pressure. At what temperature (°C) will this gas expand to a volume of 750 mL?
**Solution Approach:**
To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin) when pressure is constant.
**Charles's Law Formula:**
\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]
Where:
- \( V_1 \) is the initial volume of the gas (347 mL),
- \( T_1 \) is the initial temperature (in Kelvin),
- \( V_2 \) is the final volume of the gas (750 mL),
- \( T_2 \) is the final temperature (in Kelvin).
**Converting Temperatures to Kelvin:**
- Initial temperature \( T_1 \):
\[ T_1 = -37.5 °C + 273.15 = 235.65 \text{ K} \]
**Setting Up the Equation:**
\[
\frac{347}{235.65} = \frac{750}{T_2}
\]
**Solving for \( T_2 \):**
\[
T_2 = \frac{750 \times 235.65}{347}
\]
**Converting Back to Celsius:**
After calculating \( T_2 \) in Kelvin, convert it back to Celsius by subtracting 273.15.
**Graphical Explanation:**
If a graph were provided, it would typically show the direct relationship between Temperature (x-axis) and Volume (y-axis). The line should ideally be straight, illustrating the linearity between the two variables as per Charles's Law.
**Answer Box:**
An input field for students to enter their calculated temperature in Celsius.
By solving this equation, students will gain a deeper understanding of the direct proportionality between the volume and temperature of a gas under constant pressure.
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