A student prepared a 250.0 mL solution by dissolving 4.559 g of (NH4)2SO4 in enough water. The temperature is 298 K. The base dissociation constant for NH3 is 1.796x10-5. Please answer the following questions. A. B. C. What is the equilibrium concentration of H3O+ in the solution? Please provider your answer below. 0² 0₂ What is the equilibrium concentration of OH in the solution? Please provider your answer below. Q S □ → ² S П What is the pH of the solution? pH = Please provider your answer below. O S (7 A M M

A student prepared a 250.0 mL solution by dissolving 4.559 g of (NH4)2SO4 in enough water. The temperature is 298 K. The base dissociation constant for NH3 is 1.796x10-5. Please answer the following questions. A. B. C. What is the equilibrium concentration of H3O+ in the solution? Please provider your answer below. 0² 0₂ What is the equilibrium concentration of OH in the solution? Please provider your answer below. Q S □ → ² S П What is the pH of the solution? pH = Please provider your answer below. O S (7 A M M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The Ka for a weak acid is 1.2*10^-8. a. What is the equilibrium concentration of OH- in a 0.0020 M solution of the conjugate base? b. What is the equilibrium concentration of the undissociated conjugate base in a 0.0020 M solution of the conjugate base? c. What is the equilibrium pH of a 0.0020 M solution of the conjugate base?
5. Determine the pH of the solution which has 10% of NaOH in deionized water by mass. The NaOH which was used to prepare 10% solution has a density of 1.131kg/L. Assumption: 100 % dissociation. N2OH + Na* + OH
I need help with questions 5-8?
Order these chemical species by increasing pH of an 0.1 M aqueous solution of each. That is, imagine making an 0.1 M solution of each species. Select 1 next to the species that makes the solution with the lowest pH. Select 2 next to the species that makes the solution with the next higher pH, and so on. Notice that some of the rankings have been filled in for you already. Also notice that water is on the list. For that particular case, just compare the pH of pure water to the pH of the other solutions. Note for advanced students: for all charged species, you may assume the necessary counterions act as neither acids nor bases. species ΙΟ HF HIO F ОН NO₂ HNO₂ H₂O relative pH of 0.1 M aqueous solution (Choose one) (Choose one) 3 5 8 (highest) (Choose one) 2 (Choose one) X Ś
One water molecule can donate a proton to another in a process called the equilibrium constant expression for this reaction is O a. #,0* ][ OF] [H,0] он autoionization; Ob. [H,0* ][ O] [H,0]° protonation; Oc. [H,0* ][O ] [H,0] hydrolysis; Od. autoionization; [H30*][OH] Oe. [H,0* ][O ] [H,0] OHO neutralization;
Order these chemical species by increasing pH of an 0.1 M aqueous solution of each. That is, imagine making an 0.1 M solution of each species. Select 1 next to the species that makes the solution with the lowest pH. Select 2 next to the species that makes the solution with the next higher pH, and so on. Notice that some of the rankings have been filled in for you already. Also notice that water is on the list. For that particular case, just compare the pH of pure water to the pH of the other solutions. Note for advanced students: for all charged species, you may assume the necessary counterions act as neither acids nor bases. species relative pH of 0.1 M aqueous solution + C6H5NH3 HCOOH 3 2 HCOO (Choose one) H₂O HONH3 5 + (Choose one) C6H5NH2 (Choose one) H₂O+ (Choose one) HONH2 8 (highest)
4. THE ANSWERS ON THE QUESTIONS MUST BE SIMILAR TO THE FOLLOWING: a. X(OH)2(s) ⇌ X2+(aq) + 2OH-(aq) ; Ksp = [X2+][OH−]2; Ksp = (s)(2s)2 b. s = 3.1 x 10–4 M c. Ksp = 1.2 x 10–10SHOW THE COMPLETE SOLUTION CLEARLY.
Imagine that 500 mL of a 0.100 M solution of HOAc(aq) is prepared. What will be the [OAc–] at equilibrium in this solution if the acid dissociation constant Ka(HOAc) = 1.79 x 10–5? a. 1.33 x 10–3 M b. 4.23 x 10–3 M c. 9.46 x 10–4 M d. 0.100 M e. not enough information to tell
Calculate the pH and fraction of dissociation (a) for each of the acetic acid (CH COOH, pka = 4.756) solutions. A 0.00333 M solution of CH, COOH. A 2.15 x 10-12 M solution of CH, COOH. pH = 1 228 X10-7
b. I'm falling asleep.... The CO₂ concentration in a classroom can increase over the lecture period due to poor ventilation. You decide to measure the pH of pure water in contact with the atmosphere as an indirect way to determine whether you have adequate ventilation. You measure a pH value of 5.3. Assuming equilibrium, i. What is the concentration of CO2 in the classroom? ii. How does the value you calculated compare to the recommended safe level of 800-1000 ppm?
Which of the following statement best explain why the acidity of carboxylic acids is greater than those of the alcohols? a. Alcohols behave as neutral compounds in aqueous solution. b. Alcohol has the ability to donate proton to becomes a negative ion called an alkoxide ion, RO– c. When a carboxylic acid donates its proton, it becomes a negatively charged ion, RCOO−, called a carboxylate ion which is more stabilized by resonance. d. The OH group in alcohol is less charged and often more difficult to release electron for chemical reactions.
Order these chemical species by increasing pH of an 0.1 M aqueous solution of each. That is, imagine making an 0.1 M solution of each species. Select 1 next to the species that makes the solution with the lowest pH. Select 2 next to the species that makes the solution with the next higher pH, and so on. Notice that some of the rankings have been filled in for you already. Also notice that water is on the list. For that particular case, just compare the pH of pure water to the pH of the other solutions. Note for advanced students: for all charged species, you may assume the necessary counterions act as neither acids nor bases. relative pH of species 0.1 M aqueous solution HC₂04 7 + H₂O* 1 (lowest) H₂PO4 (Choose one) H₂PO4 4 103 (Choose one) HIO₂ H₂C₂O4 (Choose one) H₂O (Choose one)