Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
A student performs the lab as described. Leaving the object and 10 cm lens in place, a student places the 5 cm lens 35 cm away from the 10 cm lens. a) Calculate the object distance for the 5 cm lens. b) Calculate the image distance from the 5 cm lens. c) Calculate the magnification of the 5 cm lens. d) Calculate the total magnification from both lenses. e) Calculate the expected final image height (from both lenses). f) Is the final image upright or inverted?

A student performs the lab as described. Leaving the object and 10 cm lens in place, a student places the 5 cm lens 35 cm away from the 10 cm lens. a) Calculate the object distance for the 5 cm lens. b) Calculate the image distance from the 5 cm lens. c) Calculate the magnification of the 5 cm lens. d) Calculate the total magnification from both lenses. e) Calculate the expected final image height (from both lenses). f) Is the final image upright or inverted?

icon
Related questions
Question

A student performs the lab as described. Leaving the object and 10 cm lens in place, a student places the 5 cm lens 35 cm away from the 10 cm lens. 


a) Calculate the object distance for the 5 cm lens.

b) Calculate the image distance from the 5 cm lens.

c) Calculate the magnification of the 5 cm lens.

d) Calculate the total magnification from both lenses.

e) Calculate the expected final image height (from both lenses).

f) Is the final image upright or inverted?

PHY109 Lab 8 SUMMARY In this lab you will measure the locations and sizes of images formed by converging lenses and verify that your results agree with the lens equation. THEORY An object placed a distance do in front of a lens of focal length f produces an image at a distance di, where the relation between do, f and di is given by the lens equation, 1+1=1 do di The Formation of Images by Lenses THE FORMATION OF IMAGES BY LENSES f The magnification of the image, m, is the ratio of the image height, h; to the object height, ho, and can also be calculated via the magnification equation, = Yobj When two lenses are used together, as shown at right, the image from the first lens becomes the object for the second lens. Each lens individually obeys the lens equation and the distance between the lenses, s, is the sum of the image distance of the first lens and object distance of the second. The total magnification from a double-lens system is the product of the magnification from each individual lens. dobi -di hi m = ho do where a negative magnification means the image is inverted (note that the diagrams use y in place of h for heights). y1obj Object and image locations. The magnification in this case is negative (the image is on the opposite side of the axis). d1 obj d1 dimage image S d2 obj d1 image - Yimage - y1 image= - y2 obj The image formed by two lenses used together. y2 obj
Transcribed Image Text:PHY109 Lab 8 SUMMARY In this lab you will measure the locations and sizes of images formed by converging lenses and verify that your results agree with the lens equation. THEORY An object placed a distance do in front of a lens of focal length f produces an image at a distance di, where the relation between do, f and di is given by the lens equation, 1+1=1 do di The Formation of Images by Lenses THE FORMATION OF IMAGES BY LENSES f The magnification of the image, m, is the ratio of the image height, h; to the object height, ho, and can also be calculated via the magnification equation, = Yobj When two lenses are used together, as shown at right, the image from the first lens becomes the object for the second lens. Each lens individually obeys the lens equation and the distance between the lenses, s, is the sum of the image distance of the first lens and object distance of the second. The total magnification from a double-lens system is the product of the magnification from each individual lens. dobi -di hi m = ho do where a negative magnification means the image is inverted (note that the diagrams use y in place of h for heights). y1obj Object and image locations. The magnification in this case is negative (the image is on the opposite side of the axis). d1 obj d1 dimage image S d2 obj d1 image - Yimage - y1 image= - y2 obj The image formed by two lenses used together. y2 obj
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 5 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer