A student performs the lab as described. Leaving the object and 10 cm lens in place, a student places the 5 cm lens 35 cm away from the 10 cm lens. a) Calculate the object distance for the 5 cm lens. b) Calculate the image distance from the 5 cm lens. c) Calculate the magnification of the 5 cm lens. d) Calculate the total magnification from both lenses. e) Calculate the expected final image height (from both lenses). f) Is the final image upright or inverted?
A student performs the lab as described. Leaving the object and 10 cm lens in place, a student places the 5 cm lens 35 cm away from the 10 cm lens. a) Calculate the object distance for the 5 cm lens. b) Calculate the image distance from the 5 cm lens. c) Calculate the magnification of the 5 cm lens. d) Calculate the total magnification from both lenses. e) Calculate the expected final image height (from both lenses). f) Is the final image upright or inverted?
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Question
A student performs the lab as described. Leaving the object and 10 cm lens in place, a student places the 5 cm lens 35 cm away from the 10 cm lens.
a) Calculate the object distance for the 5 cm lens.
b) Calculate the image distance from the 5 cm lens.
c) Calculate the magnification of the 5 cm lens.
d) Calculate the total magnification from both lenses.
e) Calculate the expected final image height (from both lenses).
f) Is the final image upright or inverted?
Transcribed Image Text:PHY109 Lab 8
SUMMARY
In this lab you will measure the locations and sizes of images formed by converging lenses and verify
that your results agree with the lens equation.
THEORY
An object placed a distance do in front of
a lens of focal length f produces an
image at a distance di, where the
relation between do, f and di is given by
the lens equation,
1+1=1
do
di
The Formation of Images by Lenses
THE FORMATION OF IMAGES BY LENSES
f
The magnification of the image, m, is
the ratio of the image height, h; to the
object height, ho, and can also be
calculated via the magnification
equation,
=
Yobj
When two lenses are used together, as
shown at right, the image from the first
lens becomes the object for the second
lens. Each lens individually obeys the
lens equation and the distance between
the lenses, s, is the sum of the image
distance of the first lens and object
distance of the second. The total
magnification from a double-lens system
is the product of the magnification from
each individual lens.
dobi
-di
hi
m =
ho do
where a negative magnification means the image is inverted (note that the diagrams use y in place
of h for heights).
y1obj
Object and image locations. The magnification in this case is
negative (the image is on the opposite side of the axis).
d1 obj
d1
dimage
image
S
d2 obj
d1
image
- Yimage
- y1 image= - y2 obj
The image formed by two lenses used together.
y2 obj
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