A student performs a lab using a pair of coils with radius R = 10.5 cm and N = 95 windings. Using the equation in the theory, calculate the magnetic field at the center of both coils when the coil current is 4.7 A. THEORYWhen an electron is accelerated through a potential (voltage) difference V, the work done on theelectron (eV) equals the change in kinetic energy2eV1-mv² = eV ⇒V=2(1)where m is the electron mass, e is the elementary charge and v the electron velocity.An electron moving perpendicular to a magnetic field B is subject to a force of magnitude2eVF = eBv = eB(2)mwhich is perpendicular to the electron velocity and the magnetic field, and therefore causes theelectron to move in a circle. The centripetal force required for a circular orbit of radius r isF=m-(3)rEquating the two expressions for F and solving for velocity givesV²eBrF=mrmCombining the above with equation 1 leads to an equation for the charge-to-mass ratio2eV eBre2VB(z)m===(5)mmm B²r²If the voltage (V), the magnetic field (B) and the radius of the circular electron path (r) aremeasured, the charge-to-mass ratio can be calculated using this equation.eBv ⇒v=The magnetic field that the electron moves through is created using two parallel coils (see thephotos on the next page). At a distance z from the center of a single coil the field isHoNIR ²(6)B = 2-2[R² +2²7³/²where μ. = 4 x 10-7 T-m/A, R is the radius of the coil, N is the number of times the wire is woundaround the coil, and I is the current. In this case we have two coils, both a distance z = R/2 fromthe electron beam in the vacuum tube. The field is thusHoNIR 2RPor(9)7²R² +2(4)⇒ B=8MONI125 R(7)

Given:- Radius of both coils (R) = 10.5 cm = 10.5×10-2 m Number of turns or…

A student performs a lab using a pair of coils with radius R = 10.5 cm and N = 95 windings. Using the equation in the theory, calculate the magnetic field at the center of both coils when the coil current is 4.7 A

A student performs a lab using a pair of coils with radius R = 10.5 cm and N = 95 windings. Using the equation in the theory, calculate the magnetic field at the center of both coils when the coil current is 4.7 A

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 80P

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