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A student multiplied 1+x and * His solution is presented below 2-x x-1 1+x (x-1)( x+1) #. Is his solution correc. %3D 2-x 1-x (2-хX1-х) 2-x No. There is no common factor to both numerator and denominator No. The multiplier must be reciprocated before multiplying the expressions. No. Common variables must be eliminated No. Dividing (x - 1) by (1 – x) is not equal to 1.

A student multiplied 1+x and * His solution is presented below 2-x x-1 1+x (x-1)( x+1) #. Is his solution correc. %3D 2-x 1-x (2-хX1-х) 2-x No. There is no common factor to both numerator and denominator No. The multiplier must be reciprocated before multiplying the expressions. No. Common variables must be eliminated No. Dividing (x - 1) by (1 – x) is not equal to 1.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A student multiplied x-1 1+x and * His solution is presented below 2-x 1-x 1+x (x-1)( x+1) Is his solution correct? 2-x 1-x (2-х)(1-х) No. There is no common factor to both numerator and denominator No. The multiplier must be reciprocated before multiplying the expressions. No. Common variables must be eliminated No. Dividing (x - 1) by (1 – x) is not equal to 1.
Transcribed Image Text:A student multiplied x-1 1+x and * His solution is presented below 2-x 1-x 1+x (x-1)( x+1) Is his solution correct? 2-x 1-x (2-х)(1-х) No. There is no common factor to both numerator and denominator No. The multiplier must be reciprocated before multiplying the expressions. No. Common variables must be eliminated No. Dividing (x - 1) by (1 – x) is not equal to 1.
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