A student is looking up to the top of a building. The point he is looking at is 5,000 feet away. Find distance (1 between the student and the entrance of the building. 5000ft 5° 5000-

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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A student is looking up to the top of a building. The point he is looking at is 5,000 feet away. Find distance (
between the student and the entrance of the building
5000ft
a
A. a=5000sin(5)
B. a-5000cos(5)
5000
C. a =
zin(5)
5000
D. a =
cos(51
R.
Transcribed Image Text:A student is looking up to the top of a building. The point he is looking at is 5,000 feet away. Find distance ( between the student and the entrance of the building 5000ft a A. a=5000sin(5) B. a-5000cos(5) 5000 C. a = zin(5) 5000 D. a = cos(51 R.
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