A student is determining the enthalpy of solution for ammonium nitrate by adding ammonium nitrate to a calorimeter and measuring the temperature change. The accepted value is ΔΗ. = 25.7 kJ/mol. 'sol'n A student, not paying attention, adds 1.5g of ammonium nitrate instead of 1.0g. When they perform their calculations, they use 1.0g as the mass. Will their calculation result in an answer that is higher than the accepted value or lower? Explain.
A student is determining the enthalpy of solution for ammonium nitrate by adding ammonium nitrate to a calorimeter and measuring the temperature change. The accepted value is ΔΗ. = 25.7 kJ/mol. 'sol'n A student, not paying attention, adds 1.5g of ammonium nitrate instead of 1.0g. When they perform their calculations, they use 1.0g as the mass. Will their calculation result in an answer that is higher than the accepted value or lower? Explain.
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:6.
A student is determining the enthalpy of solution for ammonium nitrate by adding
ammonium nitrate to a calorimeter and measuring the temperature change.
The accepted value is
ΔΗ. = 25.7 kJ/mol.
sol'n
A student, not paying attention, adds 1.5g of ammonium nitrate instead of 1.0g.
When they perform their calculations, they use 1.0g as the mass.
Will their calculation result in an answer that is higher than the accepted value or
lower? Explain.
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