A student goes to the library. Let events B= the student checks out a book and D= the student check out a DVD. Suppose that P(B)=0.54 P(D)=0.45 and P(D|B)=0.50   Round each answer to four decimal places. (a) Find P(B′) Enter the exact answer. P(B′)=     (b) Find P(D AND B) Enter the exact answer. P(D AND B)=      (c) Find P(B|D). Round your answer to three decimal places. P(B|D)=     (d) Find P(D AND B′) Enter the exact answer. P(D AND B′)=     (e) Find P(D∣B) Enter the exact answer. P(D∣B′)

Q: Find the value of X

A: in circle

Q: Given P(A) = 0.7 and P(B) = 0.8. If P(A/B) = 0.3 find P(A and B).

A: Given that  P(A)=0.7 , P(B)=0.8 P(A/B)=0.3

Q: If e7 19, then x =

A:

Q: P(A U B) = 0.9, P(B) = 0.8, P(A n B) = 0.5. Find P(A). %D

A: We have given that,  P(A∪B) = 0.9, P(B) = 0.8 and P(A∩ B) = 0.5 Then,  We will find P(A) = ?

Q: p(a)= 0.7 p(b)=0.2 and A and B are mutually exclusive, find p(A and B)

A: Given that  p(A)=0.7 , p(B)=0.2

Q: p(e and f) is 0.4 and p(e) is 0.8 what is p(f|e) ?

A: Given,P(e and f) = 0.4and P(e) = 0.8

Q: P ( Z > - 170) =

A:

Q: Given P(E or F) = 0.86, P(F) = 0.26, and P(E and F) = 0.02, what is P(E)?

A: Given P(E or F) = 0.86, P(F) = 0.26, and P(E and F) = 0.02, By the addition theorem  P(EorF) =P(E)…

Q: Find  P4 . (b) Find  PMore than 2 .

A: The probability of correctly answering a question = 1/5 n = 7

Q: Simplify (ex)3. e(9x + 2) to the form e Ax + B) – eº .ex where %3D 21 B= 2 C = 2 D= 21/2 Xくくく

A: To simplify the following expression

Q: Let P(A)=P(A)= 0.282.   Find P(A¯¯¯¯)P(A¯). Do not round your answer.

A: From the provided information, The probability of event A, P (A) = 0.282

Q: 44. What is the value of E(X + 3)² for the scores: 1, 5, 7, 11?

A: Given score is 1, 5, 7, 11

Q: Z score of 0.045

A:

Q: Simplify. (10 – 4)! (10 – 4)! =

A: Given : (10-4)!

Q: Find all values of x for which rank(A) = 2. 1205 A = x= 0 2 7 x 19 -3 -3 -2 -6

A:

Q: Given P(E or F) = 0.83, P(E) = 0.44, and P(E and F) = 0.18, what is P(F)?

A: P(E or F) = P(E) + P(F) - P(E and F)