both part a and b are correct. Units are in meters and seconds. please solve for Part C PinPin0.660.66Parts A and BPart C PartDescriptionAnswerSaveA thin-straight uniform rod of length0.66 m hangs from a pivot at theend of the rod. What is the period of secoscillation?А: 1.331A.C: 1.331 s1 hint available(include units with answer)What is the length of a simplependulum that will have the sameperiod?(include units with answer)A: .44mC: 0.4400A student drills a hole and inserts apivot pin such that the rod oscillatesat a period of 1.23 times the originalperiod. At what distance x shouldshe drill the hole?Format CheckС.OK - using firstvalue as 0.472m(include units with answer)4 hints available1 IV check availableB.

The new moment of inertia of rod, I=ML212+ML2-x2 New time period, T=1.23×1.331 sec=1.637 sec

Answered: A student drills a hole and inserts a…

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A student drills a hole and inserts a pivot pin such that the rod oscillates at a period of 1.23 times the original period. At what distance x should she drill the hole? (include units with answer)