A student determines the value of the equilibrium constant to be 7.74x10-37 for the following reaction. H₂S(g) + 2H₂O(l) 3H₂(g) + SO₂(g) Based on this value of Keq AG for this reaction is expected to be (greater, less) Calculate the free energy change for the reaction of 2.10 moles of H₂S(g) at standard conditions at 298K. AGxn= kj than zero.

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A student determines the value of the equilibrium constant to be 7.74x10-37 for the following reaction.
H₂S(g) + 2H₂O(l) →→→→3H₂(g) + SO₂(g)
Based on this value of Keq
AG° for this reaction is expected to be (greater, less)
Calculate the free energy change for the reaction of 2.10 moles of H₂S(g) at standard conditions at 298K.
AG rxn
kj
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than zero.
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Transcribed Image Text:A student determines the value of the equilibrium constant to be 7.74x10-37 for the following reaction. H₂S(g) + 2H₂O(l) →→→→3H₂(g) + SO₂(g) Based on this value of Keq AG° for this reaction is expected to be (greater, less) Calculate the free energy change for the reaction of 2.10 moles of H₂S(g) at standard conditions at 298K. AG rxn kj Submit Answer Retry Entire Group than zero. 4 more group attempts remaining
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