A student determines the value of the equilibrium constant to be 6.71×10' for the following reaction. CO(g) + H,0(1)–→CO2(g)+ H2(g) Based on this value of Kea than zero. AG° for this reaction is expected to be (greater, less) Calculate the free energy change for the reaction of 2.26 moles of CO(g) at standard conditions at 298K. AG° kJ rxn

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A student determines the value of the equilibrium constant to be 6.71×10³ for the following reaction.
CO(g) + H,0()→CO2(g) + H,(g)
Based on this value of Keg:
than zero.
AG° for this reaction is expected to be (greater, less)
Calculate the free energy change for the reaction of 2.26 moles of CO(g) at standard conditions at 298K.
AG°,
kJ
rxn
Transcribed Image Text:A student determines the value of the equilibrium constant to be 6.71×10³ for the following reaction. CO(g) + H,0()→CO2(g) + H,(g) Based on this value of Keg: than zero. AG° for this reaction is expected to be (greater, less) Calculate the free energy change for the reaction of 2.26 moles of CO(g) at standard conditions at 298K. AG°, kJ rxn
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