A student creates a sports drink by dissolving 5.0 g of powder in 250 mL of water. The green colour of the drink is due to the presence Green Dye X, which has a lambdamax of 630 nm. A calibration curve (absorbance versus concentration) at lambdamax is created for varying concentrations (mM) of Green Dye X which has the equation y = 26.4x. If 1.0 mL of the sports drink is diluted to 10. mL with water, then the absorbance is measured to be 0.450, what is the mass percent of Green Dye X in the drink powder if the molecular weight is 418.4 g mol-
A student creates a sports drink by dissolving 5.0 g of powder in 250 mL of water. The green colour of the drink is due to the presence Green Dye X, which has a lambdamax of 630 nm. A calibration curve (absorbance versus concentration) at lambdamax is created for varying concentrations (mM) of Green Dye X which has the equation y = 26.4x. If 1.0 mL of the sports drink is diluted to 10. mL with water, then the absorbance is measured to be 0.450, what is the mass percent of Green Dye X in the drink powder if the molecular weight is 418.4 g mol-1?
Given:
The amount of powder dissolved in 250 mL of water is 5.0 g. The value of the straight line obtained from a calibration curve is y = 26.4x. The molar mass of Green dye X is 418.4 g/mol.
Step by step
Solved in 4 steps
