Answered: A student carries out a titration to…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A student carries out a titration to find the concentration of 65.0ml of HCl using 0.250M NaOH. The initial volume of NaOH in the burst is 10.40mL. The final volume of NaOH in the buret is 42.0mL. what is the concentration of the HCl in molarity?

Expert Solution

Step 1

Titration, is the process which help to determine, the concentration of unknown solution by titrating to the known solution concentration.

Step 2

Given information:

Volume of $HCl$ solution = $65 mL$

Concentration of $NaOH$ solution = $0.250 M$

Initial volume of $NaOH$ in burette = $10.40 mL$

Final volume of $NaOH$ in burette = $42 mL$

Total volume of $NaOH$ used = $Final volume - initial volume$

= $42 mL-10.40mL$

= $31.6 mL$

Expression for number of moles is given by:

$Molarity = \frac{Number of moles}{Volume} Number of moles = Molarity \times Volume$

Substituting, $31.6 mL$ volume and $0.250 M$ concentration in the expression:

$Number of moles = 0.250 M×31.6 mL = 7.9 milimoles$

Number of moles of $NaOH$ is $7.9 milimoles$ .

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