A STuare footing is 1.8 x 1.8 m with a 0.4 × 0.4 m? square column. It is loaded with an zxia! load of 1800 kN and M d'-36° and c'=20 kPa. The footing depth D= 1.8 m, the soil unit weight y = 18 kN/m³, the water table is at a depth of 4.2 m from the ground surface. What is the ultimate load Qu by using general bearing capacity equation. 810 kN.m; My 260 kN.m. Undrained triaxial tests give %3D Given (- (0.62 ,0.66 ,0.68 (0.72) and 2- (0.20 (0.24),0.28,0.32) L
A STuare footing is 1.8 x 1.8 m with a 0.4 × 0.4 m? square column. It is loaded with an zxia! load of 1800 kN and M d'-36° and c'=20 kPa. The footing depth D= 1.8 m, the soil unit weight y = 18 kN/m³, the water table is at a depth of 4.2 m from the ground surface. What is the ultimate load Qu by using general bearing capacity equation. 810 kN.m; My 260 kN.m. Undrained triaxial tests give %3D Given (- (0.62 ,0.66 ,0.68 (0.72) and 2- (0.20 (0.24),0.28,0.32) L
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Given (4-
A sTIere footing is 1.8 x 1.8 m with a 0.4 x 0.4 m2 square column. It is loaded with an
arial load of 1800 kN and Mx = 810 kN.m; My= 260 kN.m. Undrained triaxial tests give
-36° and c'=20 kPa. The footing depth D = 1.8 m, the soil unit weight y = 18 kN/m³, the
water table is at a depth of 4.2 m from the ground surface. What is the ultimate load Qu by
using general bearing capacity equation.
→ (0.62 ,0.66 ,0.68(0.72) and 2- (0.20 (0.24), 0.28 ,0.32)
->
L](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff8d7be27-a75b-4b66-99e5-7fef434c8a78%2F0f2944b7-8b08-41ac-931b-9ab94ba22c38%2Fualrsjj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given (4-
A sTIere footing is 1.8 x 1.8 m with a 0.4 x 0.4 m2 square column. It is loaded with an
arial load of 1800 kN and Mx = 810 kN.m; My= 260 kN.m. Undrained triaxial tests give
-36° and c'=20 kPa. The footing depth D = 1.8 m, the soil unit weight y = 18 kN/m³, the
water table is at a depth of 4.2 m from the ground surface. What is the ultimate load Qu by
using general bearing capacity equation.
→ (0.62 ,0.66 ,0.68(0.72) and 2- (0.20 (0.24), 0.28 ,0.32)
->
L
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