A string trimmer is a tool for cutting grass and weeds; it utilizes a length of nylon "string" that rotates about an axis perpendicular to one end of the string. The string rotates at an angular speed of 42 rev/s, and its tip has a tangential speed of 67 m/s. What is the length of the rotating string?

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Chapter 8 Homework

#### Current Attempt in Progress

A string trimmer is a tool for cutting grass and weeds; it utilizes a length of nylon "string" that rotates about an axis perpendicular to one end of the string. The string rotates at an angular speed of 42 rev/s, and its tip has a tangential speed of 67 m/s. What is the length of the rotating string?

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This problem requires understanding the relationship between angular speed, tangential speed, and the radius of rotation for the string trimmer. To solve for the length of the rotating string, you can use the formula relating tangential speed (v), angular speed (ω), and radius (r):
\[ v = r \cdot \omega \]
Given:
- Angular speed, \( \omega = 42 \) rev/s (note: you may need to convert this to radians/s)
- Tangential speed, \( v = 67 \) m/s

Solving for \( r \) will give you the length of the rotating string.

---
For additional help and resources, be sure to review the relevant section in your textbook or consult your instructor.
Transcribed Image Text:### Chapter 8 Homework #### Current Attempt in Progress A string trimmer is a tool for cutting grass and weeds; it utilizes a length of nylon "string" that rotates about an axis perpendicular to one end of the string. The string rotates at an angular speed of 42 rev/s, and its tip has a tangential speed of 67 m/s. What is the length of the rotating string? **Answer Submission:** - **Number**: [Input field for numeric answer] - **Units**: [Dropdown menu for selecting units] **Options:** - [Checkbox] Save for Later **Submission Button:** - **Attempts**: 0 of 5 used - [Submit Answer button] *Note*: Please make sure to save your progress if you wish to return to this question later. **Explanation for the Diagram/Graph:** There are no graphs or diagrams associated with this question. **Navigation:** - **Previous Page Button:** [<] - **Next Page Button:** [>] This problem requires understanding the relationship between angular speed, tangential speed, and the radius of rotation for the string trimmer. To solve for the length of the rotating string, you can use the formula relating tangential speed (v), angular speed (ω), and radius (r): \[ v = r \cdot \omega \] Given: - Angular speed, \( \omega = 42 \) rev/s (note: you may need to convert this to radians/s) - Tangential speed, \( v = 67 \) m/s Solving for \( r \) will give you the length of the rotating string. --- For additional help and resources, be sure to review the relevant section in your textbook or consult your instructor.
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