A stone weighs 280 N in alcohol (SG = 0.80) and 220 N in glycerin (SG = 1.25). What is the volume of the stone in cm? Note that the apparent weight of an object that is fully submerged in a liquid is equal to its weight in air (or simply, its weight) minus the buoyant force. Answer:
A stone weighs 280 N in alcohol (SG = 0.80) and 220 N in glycerin (SG = 1.25). What is the volume of the stone in cm? Note that the apparent weight of an object that is fully submerged in a liquid is equal to its weight in air (or simply, its weight) minus the buoyant force. Answer:
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![A stone weighs 280 N in alcohol (SG = 0.80) and 220 N in glycerin (SG = 1.25). What is the volume of the stone in cm³? Note
that the apparent weight of an object that is fully submerged in a liquid is equal to its weight in air (or simply, its weight) minus
the buoyant force.
Answer:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f2629aa-d15d-49c1-9d5b-f9fd217a3abd%2Ff96528c3-64cd-4379-a528-630c6c77ce3a%2F6j9xevo_processed.png&w=3840&q=75)
Transcribed Image Text:A stone weighs 280 N in alcohol (SG = 0.80) and 220 N in glycerin (SG = 1.25). What is the volume of the stone in cm³? Note
that the apparent weight of an object that is fully submerged in a liquid is equal to its weight in air (or simply, its weight) minus
the buoyant force.
Answer:
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