1) A stone released at the top of the shaft of a well hits the water 1.55 s later. (a) How deep is the well? (b) At what speed does the stone hit the water? Please show all work to find constant acceleration and free fall Table 2-1 Equations for Motion withConstant Acceleration"EquationNumber2-112-152-162-172-18EquationV = V0 + atx = xo = vot + at²v² = vz + 2a(x − xo)-x − xo = 1/²/(v₁ + v)t1.2x = x₁ = vt - 1at²MissingQuantityx - XoVtaVo 2) A projectile is fired vertically up from the ground. Find its maximum height and the time offlight given that it loses 30% of its initial speed in 1.80 s and is moving upward.3) The magnitudes of the vectors C and D shown in the figure below are C = 4.0 m and D = 2.5m. Find graphically: (a) C + D; (b) C-D.

Name: 1) A stone released at the top of the shaft of a well hits the water 1
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: 1) A stone released at the top of the shaft of a well hits the water 1.55 s later. (a) How deep is the well? (b) At what speed does the stone hit the water? Please show all work to find constant acceleration and free fall Table 2-1 Equations for Moti