A stone released at the top of the shaft of a well hits the water 1.55 s later. (a) How deep is the well? (b) At what speed does the stone hit the water? Please show all work to find constant acceleration and free fall

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Chapter1: Units, Trigonometry. And Vectors
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1) A stone released at the top of the shaft of a well hits the water 1.55 s later. (a) How deep is the well? (b) At what speed does the stone hit the water? Please show all work to find constant acceleration and free fall
Table 2-1 Equations for Motion with
Constant Acceleration"
Equation
Number
2-11
2-15
2-16
2-17
2-18
Equation
V = V0 + at
x = xo = vot + at²
v² = vz + 2a(x − xo)
-
x − xo = 1/²/(v₁ + v)t
1.2
x = x₁ = vt - 1at²
Missing
Quantity
x - Xo
V
t
a
Vo
Transcribed Image Text:Table 2-1 Equations for Motion with Constant Acceleration" Equation Number 2-11 2-15 2-16 2-17 2-18 Equation V = V0 + at x = xo = vot + at² v² = vz + 2a(x − xo) - x − xo = 1/²/(v₁ + v)t 1.2 x = x₁ = vt - 1at² Missing Quantity x - Xo V t a Vo
2) A projectile is fired vertically up from the ground. Find its maximum height and the time of
flight given that it loses 30% of its initial speed in 1.80 s and is moving upward.
3) The magnitudes of the vectors C and D shown in the figure below are C = 4.0 m and D = 2.5
m. Find graphically: (a) C + D; (b) C-D.
Transcribed Image Text:2) A projectile is fired vertically up from the ground. Find its maximum height and the time of flight given that it loses 30% of its initial speed in 1.80 s and is moving upward. 3) The magnitudes of the vectors C and D shown in the figure below are C = 4.0 m and D = 2.5 m. Find graphically: (a) C + D; (b) C-D.
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