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A stone is thrown vertically upwards with an initial speed of 7 m/s. What is the velocity of the stone 3 seconds later?

A stone is thrown vertically upwards with an initial speed of 7 m/s. What is the velocity of the stone 3 seconds later?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Question: Vertical Motion** **Problem Statement:** A stone is thrown vertically upwards with an initial speed of 7 m/s. What is the velocity of the stone 3 seconds later? *Explanation:* This problem involves the concepts of vertical motion and the effects of gravity on a moving object. To solve this, we can use the following kinematic equation, taking the acceleration due to gravity (approximately \(9.8 \, \text{m/s}^2\)) into account: \[ v = u + at \] Where: - \( v \) is the final velocity. - \( u \) is the initial velocity (\(7 \, \text{m/s}\)). - \( a \) is the acceleration (gravity, but with a negative sign as it acts downwards, \(-9.8 \, \text{m/s}^2\)). - \( t \) is the time (3 seconds). By substituting the given values into the formula, you can find the velocity of the stone after 3 seconds.
Transcribed Image Text:**Physics Question: Vertical Motion** **Problem Statement:** A stone is thrown vertically upwards with an initial speed of 7 m/s. What is the velocity of the stone 3 seconds later? *Explanation:* This problem involves the concepts of vertical motion and the effects of gravity on a moving object. To solve this, we can use the following kinematic equation, taking the acceleration due to gravity (approximately \(9.8 \, \text{m/s}^2\)) into account: \[ v = u + at \] Where: - \( v \) is the final velocity. - \( u \) is the initial velocity (\(7 \, \text{m/s}\)). - \( a \) is the acceleration (gravity, but with a negative sign as it acts downwards, \(-9.8 \, \text{m/s}^2\)). - \( t \) is the time (3 seconds). By substituting the given values into the formula, you can find the velocity of the stone after 3 seconds.
Expert Solution
Step 1

Taking the upward direction as the positive y-direction.

Let acceleration be a=-g=-9.81 ms2

Intial speed, u = 7 m/s

time, t = 3 s

Speed v at time t = 3 s,

v=u+atv=u-gt=7-9.813=7-29.43=22.43 ms

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