A stone is thrown horizontally at 20 m/s from the top of a cliff 44 m high and hits the ground in 2 sec. 44 m

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Chapter1: Units, Trigonometry. And Vectors
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**Projectile Motion: Horizontal and Vertical Displacement**

**Scenario:**
A stone is thrown horizontally at a speed of 20 meters per second (m/s) from the top of a cliff that is 44 meters (m) high. The stone hits the ground in 2 seconds.

**Diagram Description:**
The diagram illustrates the motion of the stone after it is thrown horizontally from the cliff. The cliff is 44 meters high, and this height is marked on the diagram with a vertical measurement line. The trajectory of the stone is shown as a curved path, indicating its combined horizontal and vertical motion as it falls under the influence of gravity.

**Explanation:**
1. **Horizontal Motion:**
   - The stone is thrown with a horizontal velocity of 20 m/s.
   - Since there are no horizontal forces acting on the stone (neglecting air resistance), its horizontal velocity remains constant throughout its flight.

2. **Vertical Motion:**
   - The stone is subject to the acceleration due to gravity (approximately 9.8 m/s² downward).
   - The vertical displacement can be calculated using the formula for distance under constant acceleration: \( s = ut + \frac{1}{2}at^2 \)
     - Initial vertical velocity (\( u \)) = 0 (since the stone is thrown horizontally)
     - Time (\( t \)) = 2 seconds
     - Acceleration (\( a \)) = 9.8 m/s²

     Therefore, vertical displacement (\( s \)) = \( 0 \times 2 + \frac{1}{2} \times 9.8 \times (2^2) = 19.6 \times 2 = 39.2 \) meters
     - However, since the stone is thrown from a height of 44 meters, it reaches the ground in 2 seconds.

**Horizontal Distance Calculation:**
- Horizontal distance traveled = Horizontal velocity × Time
- \( \text{Distance} = 20 \text{ m/s} \times 2 \text{ s} = 40 \text{ meters} \)

Therefore, the stone travels a horizontal distance of 40 meters before hitting the ground.

**Conclusion:**
The stone, thrown horizontally from a 44-meter-high cliff at a speed of 20 meters per second, travels a horizontal distance of 40 meters in 2 seconds before hitting the ground.

**Question:**
What
Transcribed Image Text:**Projectile Motion: Horizontal and Vertical Displacement** **Scenario:** A stone is thrown horizontally at a speed of 20 meters per second (m/s) from the top of a cliff that is 44 meters (m) high. The stone hits the ground in 2 seconds. **Diagram Description:** The diagram illustrates the motion of the stone after it is thrown horizontally from the cliff. The cliff is 44 meters high, and this height is marked on the diagram with a vertical measurement line. The trajectory of the stone is shown as a curved path, indicating its combined horizontal and vertical motion as it falls under the influence of gravity. **Explanation:** 1. **Horizontal Motion:** - The stone is thrown with a horizontal velocity of 20 m/s. - Since there are no horizontal forces acting on the stone (neglecting air resistance), its horizontal velocity remains constant throughout its flight. 2. **Vertical Motion:** - The stone is subject to the acceleration due to gravity (approximately 9.8 m/s² downward). - The vertical displacement can be calculated using the formula for distance under constant acceleration: \( s = ut + \frac{1}{2}at^2 \) - Initial vertical velocity (\( u \)) = 0 (since the stone is thrown horizontally) - Time (\( t \)) = 2 seconds - Acceleration (\( a \)) = 9.8 m/s² Therefore, vertical displacement (\( s \)) = \( 0 \times 2 + \frac{1}{2} \times 9.8 \times (2^2) = 19.6 \times 2 = 39.2 \) meters - However, since the stone is thrown from a height of 44 meters, it reaches the ground in 2 seconds. **Horizontal Distance Calculation:** - Horizontal distance traveled = Horizontal velocity × Time - \( \text{Distance} = 20 \text{ m/s} \times 2 \text{ s} = 40 \text{ meters} \) Therefore, the stone travels a horizontal distance of 40 meters before hitting the ground. **Conclusion:** The stone, thrown horizontally from a 44-meter-high cliff at a speed of 20 meters per second, travels a horizontal distance of 40 meters in 2 seconds before hitting the ground. **Question:** What
**Question: What horizontal distance does it travel?**

**Options:**

- ( ) 40 m
- ( ) 15 m
- ( ) 22 m
- ( ) 880 m

In this multiple-choice question, students are asked to determine the horizontal distance traveled by an object. The options provided for the answer are 40 meters, 15 meters, 22 meters, and 880 meters. 

The question appears to be related to a physics problem involving motion, possibly projectile motion or horizontal displacement. The context of the problem is essential for determining which formula and method should be used to find the correct answer. 

If you have more context or additional details regarding the initial velocities, angles, or time of travel, it would be beneficial to analyze those factors to determine the correct horizontal distance.
Transcribed Image Text:**Question: What horizontal distance does it travel?** **Options:** - ( ) 40 m - ( ) 15 m - ( ) 22 m - ( ) 880 m In this multiple-choice question, students are asked to determine the horizontal distance traveled by an object. The options provided for the answer are 40 meters, 15 meters, 22 meters, and 880 meters. The question appears to be related to a physics problem involving motion, possibly projectile motion or horizontal displacement. The context of the problem is essential for determining which formula and method should be used to find the correct answer. If you have more context or additional details regarding the initial velocities, angles, or time of travel, it would be beneficial to analyze those factors to determine the correct horizontal distance.
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