A stone is launched vertically upward from a cliff 384 ft above the ground at a speed of 32 ft/s. Its height above the ground t seconds after the launch is given by s= - 16t + 32t +384 for 0sts6. When does the stone reach its maximum height? Find the derivative of s.

Q: х3+3x+2 5. у %3 х2-1

A: Given function: y=x3+3x+2x2-1 Differentiate the above function .w.r.t 'x' y'x=ddxx3+3x+2x2-1

Q: Find the derivative using logarithmic differentiation. Simplify you answer. Don't skip/combine…

A:

Q: 8. y = (3x² + 7)² %3D

A:

Q: y = + 1'

A:

Q: Please solve and simplify

A: To determine the first order derivative of the function.

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A:

Rate of Change

The relation between two quantities which displays how much greater one quantity is than another is called ratio.

Slope

The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as: