**Question:**A stone is dropped from the edge of a cliff and hits the ground below in 3 seconds. The height of the cliff is approximately:- ○ 45 m- ○ 30 m- ○ 90 m- ○ 10 m**Explanation:**This is a physics problem involving free fall. To find the height of the cliff, we use the formula for the distance covered by an object in free fall, which is \( h = \frac{1}{2} g t^2 \).- \( g \) is the acceleration due to gravity, approximately \( 9.8 \, \text{m/s}^2 \).- \( t \) is the time in seconds.Given \( t = 3 \, \text{s} \):\[ h = \frac{1}{2} \times 9.8 \, \text{m/s}^2 \times (3 \, \text{s})^2 \]\[ h = \frac{1}{2} \times 9.8 \times 9 \]\[ h = \frac{1}{2} \times 88.2 \]\[ h \approx 44.1 \, \text{m} \]Therefore, the height of the cliff is approximately 45 meters.

Given data: Initial velocity (V0) = 0 m/s Time (t) = 3 s Required: Height of the cliff

Answered: A stone is dropped from the edge of a…

A stone is dropped from the edge of a cliff and hits the ground below in 3 s. The hight of the cliff is approximately 45 m 30 m 90 m О 10 m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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